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8.2

hex + Ascii display problem

Asked by MellowD0c in C++ Programming Language

Tags: hex, lochar

I have run into a situation where i cannot figure out a way to display Hex with text on right site of that particular hex(by reading from file char by char and converting it to hex and displaying it). The following code only allows me to display hex with 16 chars on line, as for hex requirement that is good, but at the end of line i want to display text of that 16 chars of hex as well. How can i do it? Some code will help and if possible plz try to adjust it in the following code.


.....main........    
     while (f)
     {
          int n = 16;
          for (int i =0; i<n; i++)
          {
                  f.get(c); //get text from file
               hexed(c); //convert to hex
                         
          }
          cout << endl;
     }
                   
     return (0);
}//main ends here


void hexed(char c)
{
     char LoNibble, HiNibble, LoChar, HiChar;
     char HexTab[]= "0123456789ABCDEF";
                                        LoNibble = c & 0x0F;
     HiNibble = (c >>4) & 0x0F;
     LoChar = HexTab[ LoNibble ];
     HiChar = HexTab[ HiNibble ];
     cout << HiChar << LoChar  << " " ;
}
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[+][-]01/21/03 08:47 AM, ID: 7771767Accepted Solution

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About this solution

Zone: C++ Programming Language
Tags: hex, lochar
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Solution Provided By: jkr
Participating Experts: 4
Solution Grade: A
 
[+][-]01/21/03 09:25 AM, ID: 7772121Expert Comment

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