Convert a string to Binary & hexadecimal value

where do you want to store the result

print it, store it in a string ???

char str[] = "Test string";

// Binary
for(int i = 0; i < strlen(str); ++i)
{
  for(int k = 7; k >= 0; ++k)
    cout << ((str[i] >> k) & 1);

  cout << " ";
}
cout << endl;

// Hex
cout << setf(iob_base::hex) << str << endl;

tinchos, print it

tinchos, print it

ok, apparently i wasa late, hope its solved

imadjinn,

Your code looks simple and short, what do I write that in MFC.

Thanks

the code is simple, but full of problems.  (although I expect there are some syntax errors in mine too)  

But 1 problem is

for(int k = 7; k >= 0; ++k)
   cout << ((str[i] >> k) & 1);

nees to be

for(int k = 7; k >= 0; --k)
   cout << ((str[i] >> k) & 1);

or you have an infinite (nearly) loop.

also that might work incorrectly on some systems.  You probalby better make sure the character is treated as unsigned, like

   cout << ((unsigned char)(str[i] >> k) & 1);

>>cout << setf(iob_base::hex) << str << endl;
is hopeless.   the hex I/O manipulator won't work on a stringj, only numbers.  You could use it in a loop that converts each byte (character) of the string to a number (unsigned character) and then print that character in hex.  Like

for (int i = 0; i < strlen(str); ++i)
   cout << hex << (unsigned char) str[i];

note also that using strlen() in the loop condition is extremely inefficient.  it makes an order N operation into an order n^2 operation.

neitod,

Sorry... just early morning code :)  And yes, the strlen does add unneeded complexity to a otherwise simple function.  I thought that the

As for Bermuda, if you are using MFC you probably don't have a console window anyhow.  In that case you would need code that generates a string (or something similar) and passes it back to a function to be output in a message box or to set some window text to.  Nietod's code will work for this, and should be fairly easy to add to you app.

Here are some nrealy fully tested and debuged functions, i used them myself for a converted program. But i did have to remove some logic that prevented it from converting '\r' and '\n'. Thou it uses sprintf so it will required stdio.h.

they both return a newly allocated string and free the supplied one (thou thats easy to change). so you can do whatever needs doing with the returned string

char *StrToHexStr(char *str) {
    char *newstr = new char[(strlen(str)*2)+1];
    char *cpold  = str;
    char *cpnew  = newstr;

    while('\0' != *cpold) {
            sprintf(cpnew, "%02X", (char)(*cpold++));
            cpnew+=2;
    }
    *(cpnew) = '\0';

    delete [] str;
    return(newstr);
}

char *StrToBinStr(char *str) {
    char *newstr = new[strlen(str)*8)+1];
    char *cpold  = str;
    char *cpnew  = newstr;
   
    while('\0' != *cpold) {
            char mask = (char)0x80;
            int  i;
           
            for( i = 0; i < 8; i++) {
                if((*cpold & mask) == 0) {
                    *(cpnew++) = '0';
                } else {
                    *(cpnew++) = '1';
                }

                mask = mask >> 1;

                //the right shift isn't always defined
                //so we must make sure the new MSB is 0 ourselves
                mask = mask & 0x7F;
            }
            cpold++;
    }
    *(cpnew) = '\0';

    delete [] str;
    return(newstr);

}