Assuming x = 5 and y = 8, the following outputs are produce:
@@@@@
$$$$$
&&&&&
@@@@@
@@@@@
&&&&&
#####
$$$$$
&&&&&
*****************My Code Thus Far*********************
/* filename: hw3_txt.cpp
programer: Enrique A. De Los Santos
project: hw3.txt
purpose: dangling else problem
date: 012305 */
#include <iostream>
using namespace std;
int main() {
int x, y;
if(y == 8) {
if(x == 5)
cout << "@@@@@" << endl;
else
cout << "#####" << endl;
cout << "$$$$$" << endl;
cout << "&&&&&" << endl;
}
return 0;
}
output:
$$$$$
&&&&&
// the excercise states that by just inserting braces...this can be accomplished. The only thing I have been able to generate is the output above, and then when I move the braces...I get no output. According to the book...this can be accomplished without modifying the code. How is this possible...please advise. Del
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int x, y;
if(y == 8) {;}
if(x == 5)
{
cout << "@@@@@" << endl;
}
else
{
cout << "#####" << endl;
}
cout << "$$$$$" << endl;
cout << "&&&&&" << endl;
return 0;
}
something like this?This won't produce quite the required output but I think it might be a start for you - I recklon to solve it you have to use curly braces to un-nest the ifs.
um, actually that's wrong, the excecise (whilst odd) is correct
The trick is that they ARE uninitialised, allowing you to skip both the initial ouputs. The following works, with no additions, just rearrangement of braces and one added brace.:
int main()
{
int x, y;
//the inner if (x==5) never gets checked because y!=8
if(y == 8)
{
if(x == 5)
{
cout << "@@@@@" << endl;
}
else
{
cout << "#####" << endl;
} //end if (x==5)
}//end if (x==8)
cout << "$$$$$" << endl;
cout << "&&&&&" << endl;
system("PAUSE");
return 0;
}
produces the output:
$$$$$
&&&&&
okay...here is my output with the above changes.
******************New Code**********************
/* filename: hw3_txt.cpp
programer: Enrique A. De Los Santos
project: hw3.txt
purpose: dangling else problem
date: 012305 */
#include <iostream>
#include <iomanip>
#include <cstdlib>
using namespace std;
//const char PAUSE {;}
int main() {
int x, y;
if(y == 8) {;}
if(x == 5) {
cout << "@@@@@" << endl;
}
else {
cout << "#####" << endl;
}
cout << "$$$$$" << endl;
cout << "&&&&&" << endl;
if(y == 8) {
if(x == 5) {
cout << "@@@@@" << endl;
}
else {
cout << "#####" << endl;
} //end if (x==5)
}//end if (x==8)
cout << "$$$$$" << endl;
cout << "&&&&&" << endl;
//system("PAUSE");
return 0;
}
**************************
output:
#####
$$$$$
&&&&&
$$$$$
&&&&&
in addition to this...would like to also get:
@@@@@
$$$$$
&&&&&
@@@@@
@@@@@
&&&&&
#####
$$$$$
&&&&&
secondly...can you help with system("PAUSE");
disabled because warning states can not find pause eventhough program still runs with this warning. Curious on how to correct warning. Thank you...regards. Del
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Answer for Membership
by: pankajtiwaryPosted on 2005-01-24 at 00:24:49ID: 13119281
I am not able to understand the question. But what I can see from your code is you are trying to compare the values of x and y (which have not still been initialized) with conatant values, which is bad. Also I am confused about the actual output and expected output. Please restate your question so we will be able to help you.