The line you give just create a vector holding index long integers, each one of these being initialized to -1.
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About Vector class
Just a simple question....
When you use something like this..
vector<long> num(index,-1);
To define a vector..what does it do....I know it will orginally create a object of name "num",with ablility to hold "index" number of long integers copied from some location specified by the second argument.So what happens when you use "-1"..i guess a empty vector is created.
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Answers
The following constructor of std::vector applies to your variable:
vector(size_type n, const T& v = T(), const A& al = A());
You see, the second argument is of type const T& that defaults to T(). In your case, v was set to -1. If you omit the second argument, the result is undefined cause type long has no default constructor. However, some compilers would init the elements with 0 - according to the C++ standard.
Regards, Alex
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by: AlexFMPosted on 2005-02-28 at 23:15:29ID: 13426970
This line creates vector of long type whith index elements, every element is set to -1.