Question

Using vector, hash or linked list?

Asked by: jas_guis

I have a list of 50 strings I need to parse (in C++ - Linux env).  They are in this format:
ab/test1
ab/test2
ab/test3
ha/test1
ha/test5
ha/test6
I need to parse each string based on the /    
Once this is done - I need to add the first part of a string to a drop down box and the second part of the string in another drop down box.  For example, once the user selects "ab", the 2nd drop down box will be populated with test1, test2, test3
What container would be best to use for this?

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Asked On
2007-09-18 at 18:41:39ID22837692
Tags

list

,

vector

,

linked

Topic

C++ Programming Language

Participating Experts
3
Points
500
Comments
9

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Answers

 

by: sunnycoderPosted on 2007-09-18 at 18:47:50ID: 19917874

Hello jas_guis,

Multimap looks good for this purpose
http://www.cppreference.com/cppmultimap/index.html
http://msdn2.microsoft.com/en-us/library/1ka6hya8(VS.80).aspx

First part of your string would form the key and the second part would be the value. Multimap allows you to store entries with duplicate keys.

Regards,
sunnycoder

 

by: jkrPosted on 2007-09-18 at 18:49:40ID: 19917881

Just separate them using 'find()' e.g.

#include <string>
#include <vector>
#include <iostream>

using namespace std;

int split_text(string strIn, const char cDelim, vector<string>& vResult) {

   int nPos = 0;
   int nCount = 0;
   int nFound;
   string strToken;

   while(1) {

      nFound = strIn.find(cDelim,nPos);

      if (-1 == nFound)  {

        strToken = strIn.substr(nPos,strIn.length() - nPos);
        vResult.push_back(strToken);
        break;
      }

      strToken = strIn.substr(nPos,nFound - nPos);

      nPos = nFound + 1;

      ++nCount;

      vResult.push_back(strToken);

   }

   return nCount;
}

int main () {

   int n = split_text("ha/test6",'/',vResult);

      cout << vResult[0] << endl;
      cout << vResult[1] << endl;
}

That way, you can just separate them by accessing the individual index in the result array, i.e. 0 and 1.

 

by: jkrPosted on 2007-09-18 at 18:54:34ID: 19917893

Or, with an input list, that would be

#include <string>
#include <vector>
#include <iostream>

using namespace std;

int split_text(string strIn, const char cDelim, vector<string>& vResult) {

   int nPos = 0;
   int nCount = 0;
   int nFound;
   string strToken;

   while(1) {

      nFound = strIn.find(cDelim,nPos);

      if (-1 == nFound)  {

        strToken = strIn.substr(nPos,strIn.length() - nPos);
        vResult.push_back(strToken);
        break;
      }

      strToken = strIn.substr(nPos,nFound - nPos);

      nPos = nFound + 1;

      ++nCount;

      vResult.push_back(strToken);

   }

   return nCount;
}

int main () {

   list<string> lst;

   // fill list

   for ( list<string>::iterator i = lst.begin(); i != lst.end()) {

       int n = split_text(*i,'/',vResult);

       cout << vResult[0] << endl;
       cout << vResult[1] << endl;
    }

    return 0;
}

 

by: jkrPosted on 2007-09-18 at 18:55:23ID: 19917899

Short correction, that is

int split_text(string strIn, const char cDelim, vector<string>& vResult) {

   vResult.clear();

   int nPos = 0;
   int nCount = 0;
   int nFound;
   string strToken;

//...

 

by: itsmeandnobodyelsePosted on 2007-09-18 at 23:46:26ID: 19918659

>>>> What container would be best to use for this?
I would suggest a map<string, vector<string> >. The string key takes the first part while the vector takes all second parts to a given key:

bool fillList(string filename,  map<string, vector<string> >& m)
{
   ifstream ifs(filename.c_str());
   string line;
   while (getline(ifs, line))
   {
         int pos = (int)line.find('/');
         m[line.substr(0, pos)].push_back(line.substr(pos+1));
   }
   ifs.close();
   return !m.empty();  
}

Note, if the file can contain rubbish you may have to add some checks.

Later you simply could get the array of second values by

     vector<string>& v = m["ab"];

In case the "ab" doesn't exist an empty array was created by m["ab"]. If that is not what you want you may use the find function:

    map<string, vector<string> >::iterator f;
    if ((f = m.find("ab")) != m.end())
    {
       vector<string>& v = *f;  // get list of second values
       ...
    }

Regards, Alex

 

by: itsmeandnobodyelsePosted on 2007-09-18 at 23:49:22ID: 19918668

>>>> vector<string>& v = *f;  // get list of second values
correction: it is

    vector<string>& v = f->second;

The map manages pairs of key/value and f->second points to the value part what is a vector<string>.

 

by: jkrPosted on 2009-09-17 at 10:42:03ID: 25358897

Um, I think you missed http:#19917881 which also seperates the data in vectors using 'find()' - a method that was used later another time.

20120131-EE-VQP-002

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