Question

if(buff[0]='Q') C Question

Asked by: sudarshantk

char buff[50];
while(1)
{
            
      cout << "Enter Series of string. Q to quit" << endl;
      memset(buff, ' ', 50);
      ......
      if(buff[0]='Q') //Partially O.k, crashes the second or third or fourth ... time
          return 0;
      else
          continue;
}
Please correct the abobe code.

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Asked On
2008-07-21 at 15:55:35ID23583697
Topics

C++ Programming Language

,

C Programming Language

Participating Experts
6
Points
50
Comments
17

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Answers

 

by: Infinity08Posted on 2008-07-21 at 15:58:06ID: 22055171

First of all, it's NOT C code. It's C++.

>>       if(buff[0]='Q')

Should probably be :

      if(buff[0]=='Q')

 

by: sudarshantkPosted on 2008-07-21 at 16:39:50ID: 22055392

Sorry typing error...
 if(buff[0]=='Q')
Please try a example....first while loop is okay. Second time onwards it crashes


 

by: ozoPosted on 2008-07-21 at 17:01:38ID: 22055483

with = it exits the first time
with == it loops forever
neither crash
does your program do anything else?

#include <iostream>
#include <string.h>

using namespace std;
main(){
char buff[50];
while(1)
{
           
      cout << "Enter Series of string. Q to quit" << endl;
      memset(buff, ' ', 50);
      //......
      if(buff[0]=='Q') //Partially O.k, crashes the second or third or fourth ... time
          return 0;
      else
          continue;
}
}

 

by: sudarshantkPosted on 2008-07-21 at 17:21:02ID: 22055565

if(buff[0]=='Q') //Partially O.k, loops forever...
          return 0; //It should return....
Please let me know why the above code does not return ...it loops for ever. If Q is found it should return.

 

by: peetmPosted on 2008-07-21 at 17:22:39ID: 22055573

Stopped reading when I saw 'while(1)'

Years ago, any decent compiler would have warned you that the condition was a constant.

for(;;) was the way to code an infinite loop in C.

Maybe the C++ guys/girls[wouldn't that be welcome] will correct me and drag me into the 21st century?

 

by: ozoPosted on 2008-07-21 at 20:59:25ID: 22056360

memset(buff, ' ', 50);
will make buff[0]==' '
' ' != 'Q' so buff[0]=='Q' will always be false

buff[0]='Q' will always be true

 

by: ozoPosted on 2008-07-21 at 21:19:07ID: 22056428

if you do something else in the
      ......
to change buff[0], perhaps you also do something else to cause a crash

 

by: bandyt1712Posted on 2008-07-21 at 21:56:19ID: 22056539

BTW, when you write

   if ('Q' = buff[0])

the compiler will catch the error,
because you try to assign somthing to a constant.

 

by: Infinity08Posted on 2008-07-21 at 22:39:13ID: 22056657

sudarshantk, you really have to show us more code, and explain more about your problem. I have asked for that a few times already.

Can you show the EXACT and COMPLETE code you are using ?

 

by: CSecurityPosted on 2008-07-22 at 04:16:23ID: 22058029

in your code, your function won't return 0. because you use memset(buf,' ',50) and set all buf to ' ' and buf wont have 'Q'!!
please tell me what do you want to do? if you tell me your desired code, i can help you better.
regards

 

by: Infinity08Posted on 2008-07-22 at 13:52:20ID: 22063553

>> I see no such requests in this thread.

Take a look at his previous few questions, where my requests for clarification were ignored ;) And I wasn't shouting, merely stressing certain important words.

 

by: bandyt1712Posted on 2008-07-22 at 14:19:00ID: 22063795

As long as I watch questions at expert-exchange Infinity08 has everytime helped, even when he was short of time. So I think questions should be as exact as possible.

Regards

Andy

 

by: CSecurityPosted on 2008-07-22 at 14:42:37ID: 22063980

Dear PaulCaswell, forgive me but I want to tell something, not blame me for this, just I tell it for fun...

You recently become moderator and you need to show us a bit you are a moderator, that's why you blamed Infinity08, otherwise his comment have no problem, he was right, question is completely general and he can't get right answer with such question.... :P

Don't become angry, I just joked :P But I understood you are a moderator :D :p :)

 

by: Infinity08Posted on 2008-07-22 at 15:01:28ID: 22064123

Thank you for the support, both, but there's no problem. Paul has been around longer than me ;) And he's very good at keeping us all in check, and focused on helping out and providing a good atmosphere for everybody. That is very much appreciated btw, Paul. Don't think that's said enough.
My post might have sounded a bit harsh, but it sure wasn't meant that way. It just seemed my advice that more information is needed to get the best help possible was overlooked twice - I didn't want it to get overlooked a third time ;)

 

by: sudarshantkPosted on 2008-07-22 at 17:29:33ID: 22065018

Guys, Let me close this issue. I will open a new discussion topic, I will provide some additional code.
Since it is getting too long.

 

by: PaulCaswellPosted on 2008-07-23 at 10:41:50ID: 22071818

Hi sudarshantk,

You needn't close the thread. If no-one disagrees I could remove the off-topic comments. Just say so.

My best guess so-far is some kind of stack-clobber but I expect we'll work it out with a bit more code.

Paul

20120131-EE-VQP-002

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