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9.4

Conversion Constructor vs Conversion Operator

Asked by mkandre in C++ Programming Language, Microsoft Visual C++.Net

Tags: Conversion, Operator, Constructor, Visual C++

Is there a precedence order that is used by compilers or something of that sort in determining whether to use a conversion constructor as opposed to a conversion operator where both are available for a particular operation?

In my situation, I have two classes (say First and Second) and class first has a conversion constructor for converting class Second instances, while class Second has a conversion constructor for converting to class First type.

In essence I want the compiler to use the conversion constructor for implicit conversions but use the conversion operator for explicit conversions (i.e. casts) because although they produce the same thing in the end the processing is different. However, It keeps using (or try to use) the conversion operator by default and ignoring the conversion constructor.

I have tried making the conversion constructor private and creating a third class as a friend and using that third class to execute the conversion operator via a macro (instead of explicit casting) but the compiler generates an error saying the conversion constructor is private.

How can I solve this problem?

P.S. I'm using MS Visual C++

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             class Second; // forward declare
 
class First
{
   public:
      First();
      First(const Second&);
      // other constructors and member functions
 
   private:
      //class data
};
 
 
class Second
{
   public:
      Second();
      // other constructors and member functions
      operator First() const;
 
   private:
      //class data
};
 
 
void myFunction(First obj)
{
   //do something
}
 
 
int main()
{
   Second item;
 
   myFunction(item);
 
   return 0;
}
           
         

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Conversion Constructor vs Conversion Operator

Asked by mkandre in C++ Programming Language, Microsoft Visual C++.Net

Tags: Conversion, Operator, Constructor, Visual C++

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