Question

regular expression using c#

Asked by: warrenlyle

I am using the regular expression..

(?i)MediaBox\[\d\s\d\s\d+\s\d+\]
to find..
MediaBox[0 0 792 1224]

It works find but it can nto find digits like..

MediaBox[0 0 792.34 1224.50]

Notice how the 3rd and the 4th digits have a .34 and a .50

Thanks!

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Asked On
2007-04-30 at 08:18:07ID22542713
Topics

C# Programming Language

,

Regular Expressions

Participating Experts
2
Points
500
Comments
10

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Answers

 

by: andrewjbPosted on 2007-04-30 at 10:14:04ID: 19002922

... so replace the last two
\d+
with
\d+(\.\d+)?

 

by: warrenlylePosted on 2007-05-03 at 09:40:23ID: 19024754

but that will not work for the original one..

The one with out the .number

MediaBox[0 0 333 333]

I need  a regex that works for both...

Thanjs

 

by: andrewjbPosted on 2007-05-03 at 10:00:56ID: 19024937

It should do... The ? at the end makes the decimal part optional.

 

by: mikelodderPosted on 2007-05-04 at 11:23:00ID: 19032921

change it from \d+ to \d*
this means the digits dont have to exist

\d+
to
\d+\.?\d*

 

by: andrewjbPosted on 2007-05-04 at 11:30:42ID: 19032983

That'd work, too, but it accepts things like

23.

i.e. with a decimal point but no following digit(s). Is that OK/

 

by: mikelodderPosted on 2007-05-04 at 11:49:49ID: 19033125

Yes it does accept just a flat out decimal point.

Then this would have to be it

\d+(\.\d+)?

 

by: mikelodderPosted on 2007-05-04 at 11:50:15ID: 19033132

But this has already been tried

 

by: mikelodderPosted on 2007-05-04 at 11:50:58ID: 19033139

so may you can try this.


\d+|(\d+\.\d+)

 

by: andrewjbPosted on 2007-05-04 at 12:06:25ID: 19033256

OP : Did you actually try
\d+(\.\d+)?
(INCLUDING the final ?)
or not?

(I just wondered if you thought the ? was part of my question-like reply..)

 

by: andrewjbPosted on 2007-05-04 at 15:26:39ID: 19034418

Errrr... excuse me... I suggested that one first!

20120131-EE-VQP-002

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