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| 01.03.2008 at 03:53AM PST, ID: 23055256 |
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Attachment Details
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The Solution Rating System
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With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.
Your Input Matters If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support. Thank you! |
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using System;
using System.Collections.Generic;
using System.Text;
using System.Diagnostics;
using System.Data.SqlClient;
namespace TestApp
{
class Program
{
static void Main(string[] args)
{
using (SqlConnection connection1 = new SqlConnection(TestApp.Properties.Settings.Default.Database1ConnectionString))
{
connection1.Open();
SqlCommand command1 = new SqlCommand();
command1.Connection = connection1;
command1.CommandText = @"
declare @RC int output;
select @RC = Count(TestTableID) FROM TestTable;
";
SqlParameter param1 = new SqlParameter("@RC", System.Data.SqlDbType.Int);
param1.Direction = System.Data.ParameterDirection.Output;
command1.CommandType = System.Data.CommandType.Text;
command1.ExecuteNonQuery(); <-//ERROR: Cannot use the OUTPUT option in a DECLARE or CREATE FUNCTION statement.
object o = param1.Value;
}
}
}
}
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