Question

Size of Class in C#

Asked by: benkyoit

I have two class like then:

class A
{
    int i;
    public A(){}
    public void f() {...}
}

class B
{
    int i;
    public A(){}
    public void f1() {...}
    public void f2() {...}
    public void f3() {...}
    ....
}

And i create 2 instance of two class.

A a = new A();
B b = new B();

Which is a bigger size in memory? And how to test this?
Thanks a lot.

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Asked On
2008-04-08 at 20:46:09ID23307077
Tags

C, C#

Topic

C# Programming Language

Participating Experts
7
Points
250
Comments
14

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Answers

 

by: HardiPosted on 2008-04-08 at 21:12:15ID: 21311740

For C# 2.0 (that I use)...
As you may already know, typeof(type) cannot be used to even determine the type of string.
Because two strings of different length can have different sizes.
I think that's also the case with classes... so I don't think you can determine the size of class in C#.

 

by: HardiPosted on 2008-04-08 at 21:15:05ID: 21311751

 

by: HardiPosted on 2008-04-08 at 21:16:52ID: 21311762

sorry, on my first post, i mean sizeof(type) not typeof(type)
eg. sizeof(int)

 

by: benkyoitPosted on 2008-04-08 at 23:07:06ID: 21312110

Thanks for reply.
I know sizeof(type) not work for class. And i tried it with Marshal.SizeOf but it not worked, too.
I want to know that becauce i want to know what is disavantage when i create a class which have a lot of method. Should i divide it to many class which inheritance?

 

by: CyrexCore2kPosted on 2008-04-08 at 23:07:59ID: 21312116

I think he's just asking if the number of methods has an affect on the size of the object. Honestly I never even thought about it. It's a good question.

 

by: HardiPosted on 2008-04-08 at 23:20:14ID: 21312180

I see... as far as I know people use inheritance for good programming practice and maintainability/reusability...
As for the size and/or performance, I think it would depend on how you implement it.
eg. If you have different classes having same methods
vs if you make a new class containing the common methods, and have the classes inherit from it.
The latter would probably reduce the total size.

 

by: HardiPosted on 2008-04-08 at 23:22:03ID: 21312190

Oh... um... I'm not sure either if the number of methods affect the object size... coz I don't know a way to find the size =P

 

by: GurudenisPosted on 2008-04-08 at 23:58:48ID: 21312388

The number of methods shouldn't affect the size of the class object even if they're virtual (in which case the virtual table grows bigger, but not class instances).

 

by: Maverick_CoolPosted on 2008-04-09 at 00:59:33ID: 21312696

that makes the two classes of same size.

 

by: pradipbelePosted on 2008-04-09 at 01:27:55ID: 21312821

This is a very good topic for discussion

As far as, in calculating the size of teh object of a class,
it needs to consider folloiwng points
1) No of parameters and their datatypes
2) Any virtual method
3) Any static variable in class

So the size of teh object totally depends upon the no of parameters and their data types
If you have any virtual method., virtual table is used to store pointers

 

by: GurudenisPosted on 2008-04-09 at 03:13:25ID: 21313285

2 pradipbele:

>> 1) No of parameters and their datatypes
Do you mean member variables? Yes, they are the primary source for object size calculation.

>> 2) Any virtual method
Pointers to these are stored in the vtable, so they don't really affect the size of the object because there's at most one vtable per class, not per object. In C++, no vtable is created for a class with no virtual functions, but in C# I assume it's created anyway to support reflection.

>> 3) Any static variable in class
These do not affect the size of class objects at all, because they're shared by objects of the same class.

 

by: josgoodPosted on 2008-04-09 at 03:36:19ID: 21313384

Implementing Hardi's reference, types A, C, D, and E below are all of length 119.  Type B is longer, at 150, as one would expect.

using System;
using System.Runtime.Serialization.Formatters.Binary;

[Serializable] class A {
   public int i;
}

[Serializable] class B {
    public A anA = new A();
}

[Serializable] class C {
   public int i;
   public void f() { }
}

[Serializable] class D {
   public int i;
   public virtual void f() { }
}

[Serializable] class E : D {
   public new void f() { base.f(); }
}

class Demo {
   
   static void Main(string[] args) {
      Console.WriteLine("A size = {0}",ObjectSize(new A()));
      Console.WriteLine("B size = {0}",ObjectSize(new B()));
      Console.WriteLine("C size = {0}",ObjectSize(new C()));
      Console.WriteLine("D size = {0}",ObjectSize(new D()));
      Console.WriteLine("E size = {0}",ObjectSize(new E()));
   }

   static long ObjectSize(object o) {
      System.IO.MemoryStream stream = new System.IO.MemoryStream();
      BinaryFormatter objFormatter = new BinaryFormatter();
      objFormatter.Serialize(stream, o);
      return stream.Length;
   }
}

 

by: pradipbelePosted on 2008-04-09 at 04:07:35ID: 21313551

>> Gurudenis:
Yes Exactly. System keeps the information about class in separate memory space

 

by: kpkpPosted on 2008-04-09 at 04:46:47ID: 21313825

The size of a class instance is not affeted by the number of methods in the class definition.

I thought I'd try and prove that using the CLR Profiler (http://www.microsoft.com/downloads/details.aspx?FamilyId=A362781C-3870-43BE-8926-862B40AA0CD0&displaylang=en)

Running the attached code creates 10, 000 instances of the two classes in the original question, so any difference in instance size should be obvious to see in the profiler results.

using System;
 
namespace ConsoleApplication1
{
    class A
    {
        int i = 0;
        public A(){}
        public void f() { Program.DateTime = DateTime.Now.AddDays(i); }
    }
 
    class B
    {
        int i = 0;
        public B(){}
        public void f1() { Program.DateTime = DateTime.Now.AddDays(i); }
        public void f2() { Program.DateTime = DateTime.Now.AddDays(1); }
        public void f3() { Program.DateTime = DateTime.Now.AddDays(2); }
    }
 
    class Program
    {
        public static DateTime DateTime;
        private const int instanceCount = 10000;
 
        static void Main(string[] args)
        {
            A[] someInstancesOfA = new A[instanceCount];
            B[] someInstancesOfB = new B[instanceCount];
            for (int i = 0; i < instanceCount; i++)
            {
                someInstancesOfA[i] = new A();
                someInstancesOfB[i] = new B();
            }
        }
    }
}
                                              
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