Question

How to convert a string to list in Groovy

Asked by: michaelzhou23

Hi experts,
  I have a requirement to convert a "list-like" string into a real list in Groovy. For example, if I have a string as '[1,2,3,4,5]', how can I write a closure to convert it into a list type as [1,2,3,4,5]? If possible, could you please show me the real code?
  I'm totally new to Groovy and learning it right now.
  Thanks!

Cheers,
Michael

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Asked On
2009-04-13 at 20:03:42ID24319196
Tags

Groovy

Topic

Groovy

Participating Experts
2
Points
250
Comments
4

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Answers

 

by: mahomePosted on 2009-04-14 at 00:00:29ID: 24135486

There are likely many of possibilities in groovy. Here is one of them:

// Closure
def convertToList = { it[1..-2].split(',').collect{ it } }
 
// Example-Usage
def string = "[1,2,3,4,5]"
def result = convertToList(string)
 
println result
println result.getClass()
        

                                              
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by: TimYatesPosted on 2009-04-14 at 09:52:18ID: 24140212

This will return them as ints...

But as mahome says, there's loads of ways round this

def convertInts = { list ->
  list.tokenize( "[, ]" ).collect { it as Integer }  
}
def iList = convertInts( "[1, 2, 3, 4, 5, 11]" )
iList.each { println "$it (${it.class})" }

                                              
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by: michaelzhou23Posted on 2009-04-14 at 16:31:39ID: 24143634

Hi Thanks a lot!
I tested them and they worked. But I was wondering whether there is any way that I can put the whole things in one statement? I mean i would need this in a groovy expression.
Thanks!

 

by: TimYatesPosted on 2009-04-14 at 23:14:45ID: 24145113

?

"[1,2,3,4,5]".tokenize( "[, ]" ).collect { it as Integer }

                                              
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