I would change
<c:out value="${commandMap.model[
to
<c:out value="${commandMap.model[
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I am new to the spring framework. In my jsp i am trying to bind a form to a hashmap
I am getting this exception when i call the jsp,
org.apache.jasper.JasperEx
What is wrong in the code. Could some one please help
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Below is the HashMapCommand bean
import java.util.HashMap;
public class HashMapCommand {
private HashMap<String, Object> model = new HashMap<String, Object>();
/**
* @return the model
*/
public HashMap<String, Object> getModel() {
return model;
}
/**
* @param model the model to set
*/
public void setModel(HashMap<String, Object> model) {
this.model = model;
}
}
and my controller formbackingobject is,
protected Object formBackingObject(HttpServ
HashMapCommand command = new HashMapCommand();
command.getModel().put("us
command.getModel().put("us
Configuration config;
String configName = request.getParameter("conf
ConfigurationDAO configDAO = new ConfigurationDAOImpl();
configDAO.setDataSource(Se
config = configDAO.getByName(config
command.getModel().put("co
return command;
}
}
I also tried,
<c:out value="${commandMap.model[
even then i get the same exception.
Please help
I took the value property and now it is throwing this exception
org.apache.jasper.JasperEx
I debugged and in the controller, before sending the hashmap, i am able to see the values for userConfig
and line 38 of the jsp is,
<c:set var="userConfig" value="${commandMap.model.
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by: dravidnsrPosted on 2009-09-17 at 11:24:24ID: 25359283
can u post ur HashMapCommand??