Question

Java - Sockets, writing data and shutdownOutput

Asked by: yarabati

Greetings...

My client connects to an HTTP server by opening a socket.
Please see below source.

BufferedOutputStream bout =  new BufferedOutputStream(s.getOutputStream());
<<<DO SOMETHING TO READ DATA FROM bout<<>

When we disconnect HttpConnection, we do like below(exact order):
s.shutdownInput();
bout.flush();
s.shutdownOutput();
s.close();
socketClosed = true; // flag for reference/sake to future..

This is a working implementation and has been working with no worries for over 1500 end user access to application.
Recently our client has been intimated to us by providing logs, which we see while flushing "bout" or while s.shutdownOutput() it blocks for some time. It could be 20 minutes or 30 minutes which we can't predict.

I couldn't able to find it out whether it is creating blockage while doing one of below activities
1. bout.flush() or
2. s.shutdownOutput()

Please can anyone shed some more light on it? Thank you so much for your response in advance.


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Asked On
2009-08-28 at 03:53:09ID24689364
Topics

Java Standard Edition

,

Java Programming Language

,

J2EE

Participating Experts
3
Points
500
Comments
12

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Answers

 

by: InteractiveMindPosted on 2009-08-28 at 04:37:40ID: 25206491

Is any other information provided by the logs? (Any chance you could share them?)
Also, how often is this happening now?

By the way, shutdownOutput() automatically flushes the output stream prior to termination, so you can get rid of the bout.flush() call. Perhaps this is leading to problem...

A temporary fix: create a custom timeout monitor - you can do this by creating a separate thread to time how long it's taking to close the connection; if the time exceeds a certain value (say, 5 seconds), then the thread will just kill the socket.

 

by: CEHJPosted on 2009-08-28 at 04:53:02ID: 25206565

I too would like to see a log extract *and* the logging code that produces it

 

by: yarabatiPosted on 2009-08-28 at 05:28:47ID: 25206784


Thanks all for the replies.
Below are the logs:
2009-08-20 08:09:17,436 [SessionH] INFO: Closing output
2009-08-20 08:28:43,369 [SessionH] INFO: HttpConnection disconnected

Please note the time response. SessionH is a thread which will monitor all the sessions on our server. And will take some actions.

Please see attached code.
Any help from here, would be greatly appreciated.

public void disconnect()
    {
        if (socketClosed) return;
        try {
               	log.info("Shutting down input");
            	s.shutdownInput();
            	log.info("Shut down input");
	
              	log.debug("Closing output");
            	bout.flush();
            	s.shutdownOutput();
           	outputShutdown = true;
 
   		s.close();
            	socketClosed = true;
            	log.info("HttpConnection disconnected");
        } catch (IOException x) {
        }
    }

                                              
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by: CEHJPosted on 2009-08-28 at 05:46:13ID: 25206926

Are you sure the closing message and disconnected message belong to the same session?

 

by: yarabatiPosted on 2009-08-28 at 05:50:40ID: 25206971


Yes CEHJ. Both belonging to same session.
The original message is as below:
2009-08-20 08:09:17,436 [SessionH] <6n8lpdyD4bnduj0aVfoBrV6> DEBUG: Closing output
2009-08-20 08:28:43,369 [SessionH] <6n8lpdyD4bnduj0aVfoBrV6> INFO: HttpConnection disconnected

6n8lpdyD4bnduj0aVfoBrV6 - is our Session ID

 

by: yarabatiPosted on 2009-08-28 at 05:52:27ID: 25206989


I can say, It could be blocking in one of below locations.

bout.flush()                                      or
s.shutdownOutput()                        or
s.close()

Any thoughts or comments?

 

by: objectsPosted on 2009-08-28 at 19:49:37ID: 25212821

> I can say, It could be blocking in one of below locations.

adding some extra logging to determine exactly where it is blocking

And why are you shutting down the underlying socket instead of closing the associated stream?

bout.close() will close down the connection for you.

 

by: yarabatiPosted on 2009-09-01 at 06:54:30ID: 25231572


I am sorry guys, bit late in delay to respond.

Thanks objects & CEHJ for helping me out. One last question.

1. I have below timeout settings configured.
        s.setSoTimeout(0);
        s.setSoLinger(true, 0);
        s.setTcpNoDelay(true);

2. My question is on setting SoLinger(true,0). setting linger to "true" and linger time out to "0" means - stop reading & sending the data immediately. Data in sent & receive buffer will be DISCARDED. And finally socket will be closed immediately.

My doubt is - If the client is already expecting some data from the server (please note that there is no time out set) and we have closed our send & receive buffer by discarding it.
Is there any chance to hang at socket.close() statement, because client is already called socket.read()....??? Since, there is no socket timeout set, calling socket.read() will never gets terminated....

Any ideas?

 

by: objectsPosted on 2009-09-01 at 16:28:26ID: 25237127

you haven't answered why you are trying to close the socket explicitly
what happens when you just close the stream?

 

by: objectsPosted on 2009-09-01 at 16:29:55ID: 25237136

> 2. My question is on setting SoLinger(true,0). setting linger to "true" and linger time out to "0" means - stop reading & sending the data immediately. Data in sent & receive buffer will be DISCARDED. And finally socket will be closed immediately.

yes

 

by: yarabatiPosted on 2009-09-02 at 01:10:50ID: 25238859


> you haven't answered why you are trying to close the socket explicitly
what happens when you just close the stream?

TBF, I am not the designer of this code. Working to fix one issue. You are right, if we close the stream that should also be fine. I can keep this in my mind.

Please could you confirm my below doubt, does it make sense?

>>> My doubt is - If the client is already expecting some data from the server (please note that there is no time out set) and we have closed our send & receive buffer by discarding it.
Is there any chance to hang at socket.close() statement, because client is already called socket.read()....??? Since, there is no socket timeout set, calling socket.read() will never gets terminated....

 

by: yarabatiPosted on 2009-09-12 at 06:22:37ID: 25316444


Further, to be more clear we have added extra logs to pin point the statement which is giving the problem.

Thanks everyone here, who helped me a lot in learning the concepts.

Have a great day

20120131-EE-VQP-002

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