Question

reading from a file

Asked by: jdav3579

Hi,
I am trying to understand reading from a text file. I want to read only the last line in the file, unfortunately my usual resources such as Google are not helping me much. Is there a way that I can specify to read in from the last line. I am just doing it all from command line and its just a newbie question really, so simpler the better.
Cheers
John

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Asked On
2007-04-25 at 12:07:25ID22534088
Tags

file

,

line

,

read

,

from

Topic

New to Java Programming

Participating Experts
2
Points
250
Comments
6

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Answers

 

by: JathrekPosted on 2007-04-25 at 12:58:12ID: 18976760

I don't think there's a real way to do it directly using J2SE classes (directly accessing the last line, I mean).

Maybe you could use some kind of "hack" using RandomAccessFile;
This class gives you a "seek(n)" method, which moves your pointer to the nTh character in the file.
So, if you've some idea of the average length of a line in your file (like 200 characters), you can just go to the (fileLengthInCharacter - 200)Th character of the file and read the 200 next characters to check if there's a break line (there's a "length()" method too that returns the number of bytes in the file, you could use it to reach the end of the file).

If there's, make sure it's the last one (there could be one ten character further) and then you can just read the following characters which will then be the last line.
If there's none, just go to the (fileLengthCharacter - 400)Th character and look for a break line in the 200 next characters (and go on by step of 200 characters).

Even though it's not an official solution, I hope it'll help you.

 

by: jdav3579Posted on 2007-04-25 at 13:48:02ID: 18977187

Hi Jathrek,
Thats sort of one idea I was thinking about or may be to find out the lenght of the file and scroll backwards until a new line character is reached - but I did not like this.
What I am doing is storing 4 elements of an array as a string separated by commas in the file, but I only want the last 4 elements in the array. What I am tempted to do is read each line out and populate  the array, then read in the next line and overwrite the previous values, then when it hits the last line, it wont having anything to overwrite the values with, so leaving only the last values.

Although its only a small file, I think this is a rather ugly and possibly unreliable solution, but may get the job done, I was just checking to see if there was nothing I was missing!!!

Thanks again for your help

Cheers
john

 

by: gatorvipPosted on 2007-04-25 at 15:27:50ID: 18977881

Depending on how "elegant" you want to be and how many lines are in your file:
1) For a quick-n-dirty solution and assuming your file has relatively few lines, read the file using Scanner and only keep the last line
2) More elegant way (but it might be overkill)
http://forum.java.sun.com/thread.jspa?threadID=676327&messageID=3949951

 

by: JathrekPosted on 2007-04-25 at 23:59:43ID: 18979646

Well, yes you can do it by reading the whole file and storing each line and then overwriting the last one at each pass, but as someone who don't like to work too much with String splitting and such, I'd just say that you don't have to fill the array at each pass, you can just store the String like that and overwrite it and then just split the last one you have.

Otherwise, it seems that what you're making is quite similar to a CsvParser, so maybe you could just look for a small library to do it for you (that way, you won't really worry anymore about the quality of the code, as it'd would be some external library - and I personally feel much better when using external code than when making some not-sure-about-quality implementation on my own).

Also, if the file is only a few megabytes long, you don't really have to make something optimized for it, that'd be mostly be useless, as some bugs could be inserted in the code doing the optimization.

 

by: jdav3579Posted on 2007-07-08 at 13:42:35ID: 19441289

Thanks to both of you for your comments, apologies for the delay. I have been away with work.

20120131-EE-VQP-002

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