Question

applet wont read file

Asked by: jdav3579

Hi,
I have the following lines of code in a java applet, I am trying to read a file in the same directory on the server as the applet. When I use an applet viewer to do it, it will work but when I put it in a htm page it wont. I suspect that I need to use codeBase method somewhere in it, but I have never tried to do this before.
Any help greatly appreciated

FileInputStream myFile = null;
            try
                  {
                    myFile = new  FileInputStream(fileName);  // open the  stream
                    boolean eof = false;
                   int i=30;
                    while (!eof)
                          {
                      int byteValue = myFile.read();        // read  the stream  
                      
                      
                      if (byteValue  == -1)
                        eof = true;                                    //exit loop as end of file is reached
                      else
                         g.drawString("Integer value "+      byteValue",30,      i);
                         i+=20; //shifts down to next line
                          }
                  }
                  catch (IOException e)
                        {
                          System.out.println("Could not read file: " + e.toString());
                        }
                  finally
                        {
                          try
                                {
                            myFile.close();                          
                                }
                          catch (Exception e1)
                                {
                            e1.printStackTrace();
                                }
                        }

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Asked On
2007-06-27 at 23:53:38ID22663352
Tags

read

,

applet

,

file

Topic

New to Java Programming

Participating Experts
4
Points
500
Comments
16

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Answers

 

by: ksivananthPosted on 2007-06-27 at 23:59:36ID: 19378656

 

by: keyurkarnikPosted on 2007-06-28 at 00:00:15ID: 19378660

Is there any exception thrown there?
What happens when you try to read it in the applet?


 

by: objectsPosted on 2007-06-28 at 00:00:45ID: 19378661

You need to use URLConnection to read file on server
reason beij gthat your applet runs on the client and  not the server

 

by: ksivananthPosted on 2007-06-28 at 00:01:30ID: 19378664

if you want to get the URL of the server where the applet hosted, you can use the getCodeBase() method of the applet...

 

by: keyurkarnikPosted on 2007-06-28 at 00:03:13ID: 19378673

as your applet is running on the client, you need to user URLConenction, not FileInputStream
You have to read from a remote system

 

by: objectsPosted on 2007-06-28 at 00:03:22ID: 19378675

InputStream in = url.openStream();

 

by: ksivananthPosted on 2007-06-28 at 00:05:25ID: 19378679

see the link I have posted has an example of how tot make url connection and read a file...

 

by: jdav3579Posted on 2007-06-28 at 15:52:33ID: 19385486

Hi, Many thanks to you both for your comments.Currently as it stands I have an applet with the above code in residing in a folder on my desktop, the files it wants to open are sat in the same folder as it. When I use applet viewer, it has no problem opening the files as I want, when I try to run the web page with the applet embedded in it, it just wont open the files.... I dont know if this is something to do with the security settings etc in place on my computer. I always allow the applet to run when prompted, so I could not see it being a problem. At the moment I am not to worried about getting to run over the web or whatever, just to get it working on my computer is what I really need! Again many thanks for your help!

John

 

by: objectsPosted on 2007-06-28 at 17:04:29ID: 19385727

see my earlier comment, it is because the applet gets run on the client/browser. It does not get run in that folder on the server.
The browser downloads it and runs it locally, thats why you need to access the file via the web server using its url.

 

by: ksivananthPosted on 2007-06-28 at 22:18:12ID: 19386621

did you try the example in the link I have posted?

 

by: jdav3579Posted on 2007-06-29 at 09:56:14ID: 19391616

Hi, Thanks again to both of you, I understand now what both of you are telling me, its just that I don't exactly know how to solve the problem by integrating any of the code into the above as I am not exactly sure how it works!
I know I will have to import java.net.*
then, how do I modify this so that I get a stream of the integers from the file, as is  happening with my above code:

try {

    URL                url;
    URLConnection      urlConn;
    DataInputStream    dis;

    url = new URL("http://webserver.our-intranet.com/ToDoList/ToDoList.txt");


    urlConn = url.openConnection();
    urlConn.setDoInput(true);
    urlConn.setUseCaches(false);

    dis = new DataInputStream(urlConn.getInputStream());
    String s;
 
    toDoList.clear();
 
    while ((s = dis.readLine()) != null) {
      toDoList.addItem(s);
    }
    dis.close();
    }
    catch (MalformedURLException mue) {}
    catch (IOException ioe) {}
  }
}

 

by: jdav3579Posted on 2007-06-29 at 12:16:29ID: 19392835

I have tried the following, unfortunately it keeps telling me that there is no nextByte, I just want to read each byte out of the stream as an integer and use the integer in another part of my program.


      try {

                      URL                url;
                      URLConnection      urlConn;
                      DataInputStream    dis;
                  
                           url = new URL(getCodeBase().toString() + fileName);
                  
                      // Note:  a more portable URL:
                      //url = new URL(getCodeBase().toString() + "/ToDoList/ToDoList.txt");
                  
                      urlConn = url.openConnection();
                      urlConn.setDoInput(true);
                      urlConn.setUseCaches(false);
                  
                      dis = new DataInputStream(urlConn.getInputStream());
                      int s;
                  
                      while ((s = dis.nextByte) != null) {
                             //not null against an int not allowed
                        //output s as an integer here
                      }
                      dis.close();
                      }
                      catch (MalformedURLException mue) {}
                      catch (IOException ioe) {}

 

by: keyurkarnikPosted on 2007-06-29 at 12:30:03ID: 19392923

You might not have read permissions for the file!!

 

by: jdav3579Posted on 2007-06-29 at 12:42:02ID: 19392985

This problem is such a headache! I had my original code working no problem, would it be possible for either of you to modify my original posted code so it does the same job, but is able to read the files from where ever they are stored?? I  normally dont ask for my code to be modified, and generally work it out myself, but on this occasion I am really stuck and don't understand how to do it and need it rather urgently!!!
Thanks for all your help!

 

by: girionisPosted on 2007-08-11 at 03:38:49ID: 19675469

No comment has been added to this question in more than 21 days, so it is now classified as abandoned.

I will leave the following recommendation for this question in the Cleanup topic area:
   Split: ksivananth {http:#19378656} & keyurkarnik {http:#19378673} & objects {http:#19385727}

Any objections should be posted here in the next 4 days. After that time, the question will be closed.

girionis
EE Cleanup Volunteer

20120131-EE-VQP-002

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