let say I have a method with 2 arguments and this method will return a value with long type and I wish to update the value for x. I know that I can't declare x as long because primitive type is always 'pass by value' and I try to use Long type. I still can't get the value updated. May I know how to make this method update value of c and x?
public long methodA(long m, Long x) {
x = ....;
c = ...;
return c;
}
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Long type object is immutable, you cannot change the value of Long, once it is constructed with some value..
Better you put Long in some other object and then pass that object to the method, and change the value..
For ex..
Class MyLong
{
long value;
MyLong(long y)
{
value = y;
}
}
MyLong myLongObject = new MyLong(12);
method(12, myLongObject);
myLongObject.value will give the new value...
public long methodA(long m, MyLong x) {
x.value = newValue;
}
Hmm ... you can also :
private Long LongObject = new Long(10);
private long longPrimitive = 2;
private long longResult;
public long methodA(long m, Long x){
LongObject = new Long(LongObject.longValue(
long c = (long) LongObject.longValue() / m;
return c;
}
public someothermethod() {
System.out.println("LongOb
longResult = methodA(longPrimitive, LongObject);
System.out.println("LongOb
System.out.println("longRe
System.exit(0);
}
In fact, try to avoid static variables whenever possible, as they are prone to more errors. Any member of your class can access them. If you develop a geometry package let's say, and you want to define PI, that might be a good candidate for being 'static', and certainly a good one to be qualified as 'final'.
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by: skeid21Posted on 2008-03-11 at 20:07:17ID: 21102688
In java, you are correct all simple types are pass by value. So there is no way to change the value of the x when it is a long. If you are changing the value of x then it seems that x needs to be persistent so it would make sense to have x be a member of a class. This would be the prefered Object Oriented approach to this problem.
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