absolute path of current class file ?

Your class may not be running from a class file on disk.
It may be contained in a jar file, or loaded over the network.

try this,

public class path {
    public static void main(String[] args) {
        System.out.println(System.getProperty("user.dir") +
                                System.getProperty("file.separator") +
                                    new path().getClass().getPackage().getName());
    }
}

file is neither in jar nor in network.......it's in same machine like normal file.

 actually i am using package say
package A.B.C ;

and my file path which i need dynamically is
C:\Temp\A\B\C\XYZ.class

and i set my class path to "C:\Temp" so that i can execute my class file from any  folder.

now if i run my file from any folder, these codes gives currrent folder path only.. not what i want.......
like if i run this from
D:\Shaan folder the output will be D:\shaan not C:\Temp\A\B\C

check it out.

file is neither in jar nor in network.......it's in same machine like normal file.

 actually i am using package say
package A.B.C ;

and my file path which i need dynamically is
C:\Temp\A\B\C\XYZ.class

and i set my class path to "C:\Temp" so that i can execute my class file from any  folder.

now if i run my file from any folder, these codes gives currrent folder path only.. not what i want.......
like if i run this from
D:\Shaan folder the output will be D:\shaan not C:\Temp\A\B\C

check it out.

file is neither in jar nor in network.......it's in same machine like normal file.

 actually i am using package say
package A.B.C ;

and my file path which i need dynamically is
C:\Temp\A\B\C\XYZ.class

and i set my class path to "C:\Temp" so that i can execute my class file from any  folder.

now if i run my file from any folder, these codes gives currrent folder path only.. not what i want.......
like if i run this from
D:\Shaan folder the output will be D:\shaan not C:\Temp\A\B\C

check it out.

Try:

URL location =
  getClass().getResource("/A/B/C/XYZ.class");

file is neither in jar nor in network.......it's in same machine like normal file.

 actually i am using package say
package A.B.C ;

and my file path which i need dynamically is
C:\Temp\A\B\C\XYZ.class

and i set my class path to "C:\Temp" so that i can execute my class file from any  folder.

now if i run my file from any folder, these codes gives currrent folder path only.. not what i want.......
like if i run this from
D:\Shaan folder the output will be D:\shaan not C:\Temp\A\B\C

check it out.

U can use "System.getProperties" or "System.getProperty methods" in java.lang

Mainly

user.home - User's home directory
user.dir  - Working directory
java.class.path - Java class path
java.ext.dirs   - Path of extension directory or directories

Copycat :)

U can use "System.getProperties" or "System.getProperty methods" in java.lang

Mainly

user.home - User's home directory
user.dir  - Working directory
java.class.path - Java class path
java.ext.dirs   - Path of extension directory or directories

heartly thanks for all responses.....

 but now can any body tell me why i am getting this exception on using getPath() method over any URL object.

System.out.println (ClassLoader.getSystemClassLoader().getSystemResource("A/B/C/CurrentDirectory.class").getPath());

Exception in thread "main" java.lang.NoSuchMethodError: java.net.URL: method get
Path()Ljava/lang/String; not found
        at A.B.C.CurrentDirectory.main(CurrentDirectory.java:42)
-------------------

 even if i create url like

URL url = new URL ("http://www.yahoo.com/shaan/index.html");
String s = url.getPath() ;

gives me same error like above ...... y ?

getPath() doesn't exist in 1.1 (which is why I didn't mention it :)).

You can try using getFile() instead.

thank u object..... but i am using 1.3

 then ..... where is the problem.

Well that's strange.
From the 1.3 javadoc:

public String getPath()
Returns the path part of this URL.
Returns:
the path part of this URL.

If your compiling with 1.3 then I don't understand why it cannot find the getPath() method.

now i got the problem. It's a run time error.

 My system has both 1.2 as well as 1.3 java run time environment. so while compiling it will be taking from 1.3 and during running it will be taking from 1.2 . and getPath()  method is not there in 1.2 . this simple problem blow up my mind.

 thanks again man for ur contribution.

bye.
Shaan

Yes if you want to run the class with a lower cersion of the JVM then you cannot use the method.

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