iterative inOrder printing a tree

You need to move down the left side pushing all the nodes onto the stack, then when you hit the smallest(no more left children) you pop smallest off the top of stack and print it, test it for a right child.
  If it has one, push that child onto stack and try run down its left side, then again, you pop them back off, printing  and checking for right subtrees after you print each node.  If it doesn't have a right child pop the next off the stack, print it and check for right child.

This logic works but you'll need to form it into loops.

hi, is there anyway i can fix my original code to follow the peudocode like this

void inorder (TreeNode root)
{
  declare a stack of TreeNode, initialized as empty
  declare temp as a TreeNode
 
  start temp = root

  do
  {
    while moving temp as far left as possible,
      push tree references onto the stack

    if the stack is not empty
      reposition temp by popping the stack

    print the contents of tempgetValue()
    move temp one node to the right
  }
  while (the stack is not empty) or (temp != null)
}


thanks

void inorder ( TreeNode root )
{
  Stack stack = new Stack () ;
  NodeTree temp = root ;

  if ( temp == null )
    return ;

  do
  {
    while ( temp != null )
    {
      stack.push ( temp ) ;
      temp = temp.getLeft () ;

    } // end while

  if ( ! stack.empty () )
    temp = ( TreeNode ) stack.pop () ; // end if

  if ( temp != null )
  {
    System.out.println ( temp.getValue () ) ;
    temp = temp.getRight () ;

  } // end if

 } while ( ! stack.empty () || temp != null ) ; // end do-while

} // end of inorder ()

I didn't run that code, but I hope that you can understand what mistakes you made.

oh haaha. i figured out.
thanks a lot. it was a dumb mistake. when i print out the getValue. I shouldn't have added the (TreeNode)....

thnx guys

ya i did notice.
but is it necessary to have the checking if 'temp' is null before print?

since it's already checking before pop.

oops. clicked the wrong accepted answer............

>> clicked the wrong accepted answer

You can post a 0-point question in Community Support http://www.experts-exchange.com/Community_Support/ and ask them to re-open the question for you so that you can change the accepted answer.

>> but is it necessary to have the checking if 'temp' is null before print

Yes, because the value of temp might change with temp = temp.getLeft () ; and when it is null, it will come out of the while ( temp != null ) loop. So it means that temp is null outside this loop. Now if the stack is not empty, then a value will be popped from the stack and temp will start referring to it, otherwise, temp will be null -> so you should check if temp is null or not.

Mayank.