xmlurl=http%3A%2F%2F127.0.
I do have a method to decode the content string, however I need a method to pass in this content string and get the values for xmlurl and xslurl.
Thanks
pcorreya
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Or you can use regular expressions:
String x = "xmlurl=http%3A%2F%2F127.0
x = URLDecoder.decode(x, "UTF-8");
final String RE = "xmlurl=(.+)\\?.+xslurl=(.
Pattern p = Pattern.compile(RE);
Matcher m = p.matcher(x);
if (m.matches()) {
System.out.println(m.group
System.out.println(m.group
}
vbandaru is right, the only additional thing you may want to do is decode the urls:
import java.net.*;
public class extracturls
{
public static void main(String[] args)
{
String contentString="xmlurl=http
String xmlurl= URLDecoder.decode(contentS
String xslurl= URLDecoder.decode(contentS
System.out.println(xmlurl)
System.out.println(xslurl)
}
}
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by: vbandaruPosted on 2004-04-25 at 06:19:41ID: 10911717
The String Object has an overloaded method called indexOf. You should be able to use that in conjunction with substring to get the xmlurl and xslurl.
something like this.
String contentString="xmlurl=http
String xmlurl= contentString.substring(7,
String xslurl= contentString.substring(co