Converting an intel double byte array to a java double

sry it's not System.println();, it's System.out.println();

for(int i = 0; i < array.length; i++){
     System.out.print("[" + i + "]: " + array[i]);
}

sry, i confused with other posts
if i am right, this is ur problem
 u want to convert a char* to double i.e in java a String to Double

String num = "123.123";
Double val = Double.parseDouble(num);

System.out.println(val);

maheshexp,
  Your totally confused, I want to copy a byte array into a double

ie
byte ba[] = new byte[]{0,0,0,0,64,248,216,64};
double = convert(ba);

and then I want double to equal:  25569.000000

keeping in mind that the byte array above came form a memory dump of eight bytes running on an intel processoer

You need the following:

DataInputStream dis = new DataInputStream(new FileInputStream(pathToTheFile));
double value = dis.readDouble();

orangehead911,
  once again i'm dealing with a byte array.  Doesn't anybody ever read the damn question?????

but anyway

      java.io.ByteArrayInputStream bais = new java.io.ByteArrayInputStream(ba);
      java.io.DataInputStream in = new java.io.DataInputStream(bais);

returns: 5.385563126E-315  which is != 25569.000000

>> Doesn't anybody ever read the damn question?????
Hmmmm let's see

>>  I have a file that countains a double as written by a c program on intel.  I need to read this file from java
What is that if not the basis for your question?

Did you even try the code I posted?

Yep i tried it and got 5.385563126E-315 but when I run the above c code I got: 25569.000000  which makes your solution not work
did you try your code and get the correct answer?

>> did you try your code and get the correct answer?
I did not write a double out from a c program, I did from Java and it worked fine.

Which floating point value standard is your C compiler using?

calvinrsmith, I understand your problem, I have the same, even with integers (INTEL <-> MOTOROLA <-> VAX ...).
If you can avoid it, never exchange binary formats between different languages.
THIS IS THE STRENGTH OF JAVA: doubles are written (and read) as platform independent
and even CPU accelerator independent format.
The only thing you can do now is find out what the difference is between the source format (probably not IEEE)
and the JAVA standard. Hard work: where's the exponent, its sign, the mantissa, that's sign .....
The best way to exchange such data is in ASCII format.

And don't get angry that people overlook your question details, I've had even worse ........

;JOOP!

To the other guru's: this has nothing to do with reading/writing binaries
within a JAVA situation. So it has no use reading that byte array as a byte-file,
it was not created in JAVA, so it won't work!

;JOOP!

>> this has nothing to do with reading/writing binaries within a JAVA situation.
True

>> So it has no use reading that byte array as a byte-file,
True

>> it was not created in JAVA, so it won't work!
Not true, it has to do with the way the primitive type is serialized to disk. If this wasn't possible in Java, Java would suddenly not be as useful as it is.

Your recommendation to only write out into an easily exchangeable format is very valid, however not applicable to all situations, e.g. data files output from legacy applications.

I got it working,  
i had to modify the bytes and then or them in then finally tell java to make a double out of them

for anyone else that finds this question and wants to know how to do it visit:
http://mindprod.com/jgloss/endian.html

My code looks like this:
   byte ba[] = new byte[]{0,0,0,0,64,248,216,64};
    int currentByte = 0;
    long accum = 0;
    for ( int shiftBy = 0; shiftBy < 64; shiftBy +=8 )
    {
      // must cast to long or shift done modulo 32
      accum |= ( (long)(mdb.pg_buf[offset+currentByte++] & 0xff)) << shiftBy;
    }
    d = Double.longBitsToDouble (accum);

and d will be the correct answer: 25569.0

hmm...

Points to you!
;JOOP!