A workaround would be
int ixSep = name.indexOf(File.pathSepa
if (ixSep > -1) {
name = name.subtring(++ixSep);
}
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Question
File getName gives different results for Windows and Linux
I am suprised with the getName method in File
in Windows it gives the complete name eg : C:\Docum ,...\...\fileName
but in Linux it gives what I want the fileName
for eg:
String name =tempFile.getName();
Windows : Gives the complete Path
Linux :Gives me the Name
How do I make it to work the same for Windows and Linux
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Answers
Hey CEHJ ...what a coincidence ...it is a part of the code that you helped me with :-)
String[] filePaths = inputFiles.split(",");
String decideType =filePaths[0].toUpperCase(
String[] fileNames = new String[filePaths.length];
if(decideType.endsWith("CE
{
for(int i = 0;i < filePaths.length;i++) {
File tempFile = new File(filePaths[i]);
fileNames[i] = tempFile.getName();
System.out.println("This is the fileName\n"+fileNames[i]);
}
}
Sorry I forgot that ....will keep that in mind
// Gets the file string from the user seperated by commas ( for eg: if
// the user submits 2 files then the String would be
// /home/john/file1,/home/joh
String[] filePaths = inputFiles.split(",");
String[] fileNames = new String[filePaths.length];
for(int i = 0;i < filePaths.length;i++) {
File tempFile = new File(filePaths[i]); // Creates the file with the complete path
fileNames[i] = tempFile.getName(); // extracts the name
System.out.println("This is the fileName\n"+fileNames[i]);
}
For Linux
o/p is
file1
file2
For Woindows it is
C:\Documents and Settings\indukuri\Desktop\
C:\Documents and Settings\indukuri\Desktop\
Thanks
I cannot reproduce what you are seeing.. can you see if this program below runs as expected? If it does, then there is something else to research..
-Matt
import java.io.File;
public class FileTest {
public static void main(String[] args) {
// Gets the file string from the user seperated by commas ( for eg: if
// the user submits 2 files then the String would be
// /home/john/file1,/home/joh
String inputFiles = args[0];
String[] filePaths = inputFiles.split(",");
String[] fileNames = new String[filePaths.length];
for(int i = 0;i < filePaths.length;i++) {
File tempFile = new File(filePaths[i]); // Creates the file with the complete path
fileNames[i] = tempFile.getName(); // extracts the name
System.out.println("This is the fileName\n"+fileNames[i]);
}
}
}
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by: CEHJPosted on 2005-09-14 at 13:05:06ID: 14884329
That is odd. These are the docs:
"Returns the name of the file or directory denoted by this abstract pathname. This is just the last name in the pathname's name sequence. If the pathname's name sequence is empty, then the empty string is returned."
Can you post the code?