1) Read the string character by character and convert it to int.
2) use Integer.toBinaryString() for the above
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convert string to binary
i want to convert string which is an ip address into binary and the string is with the subnet mask like / 27 and i need to convert this as well into binary and perform and operation on it
show me the entire code from the scrach and also with an example pls
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Answers
Say You have a string:
s = "64.54.223.107/27"
Then the substrings can be converted to numbers this way:
int mask = Integer.parseInt(s.substri
s = s.substring(0, s.indexOf('/'));
int[] ip = new int[4];
String[] subs = s.split("\\.");
for(int i = 0; i < subs.length; i++)
ip[i] = Integer.parseInt(subs[i]);
after this You will have an array 'ip', containing the 4 IP numbers and a 'mask'
If You want the line
"192.123.64.0/27"
to be converted to
"192.123.64.0"
using this function:
bitwise AND of 192.123.64.0 with /27 (255.255.255.224)
Then here is a sample application:
public class IP {
public static String f(String s) {
int mask = Integer.parseInt(s.substri
s = s.substring(0, s.indexOf('/'));
int[] ip = new int[4];
String[] subs = s.split("\\.");
for(int i = 0; i < subs.length; i++)
ip[i] = Integer.parseInt(subs[i]);
long l = ip[0] << 24 | ip[1] << 16 | ip[2] << 8 | ip[3];
long lmask = ((long)Math.pow(2, mask+1) - 1) << (32 - mask);
long result = l & lmask;
return "" + ((result >> 24) & 0xFF) + "." + ((result >> 16) & 0xFF) + "." + ((result >> 8) & 0xFF) + "." + (result & 0xFF);
}
public static void main(String[] args) {
String s = "64.54.223.107/27";
System.out.println(f(s));
s = "192.123.64.0/27";
System.out.println(f(s));
}
}
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by: deepen_antivirusPosted on 2006-08-29 at 15:55:32ID: 17415899
pls be quick its very urgent