- For individual users
- Instant access to solutions
- Ask your tech questions
- Start your 30-day Free Trial
Main Topics
Browse All TopicsI used the HibernateTemplate.find(Str
Now I want to do a group by query, say "select player.age,count(player.ag
This Question has been solved and asker verified All Experts Exchange premium technology solutions are available to subscription members.
Experts Exchange has been collecting answers to technology questions since 1996…3 million and counting! If you have a question, chances are we already have your answer.
If you can't find the exact answer you're looking for, ask our exclusive community of 50,000 experts. You’ll get a personalized answer from a trusted professional.
Thousands of free tech tips, tricks, how-to’s and tutorials are available in our peer reviewed articles section. See for yourself how smart our experts are, no login required.
Access the answers to your technology questions today.
30-day free trial. Register in 60 seconds.
Members of the expert community talk about why the experience at Experts Exchange is different than what you will find anywhere else.

Try it out and discover for yourself.
30-day free trial. Register in 60 seconds.
Join the community of experts here and help other tech pros by answering question in your area of expertise. You can earn FREE access to all Experts Exchange's premium features and resources.
Business Accounts
Answer for Membership
by: yongsingPosted on 2006-09-20 at 03:13:04ID: 17559243
Each List returned contains Object[] elements, and each of the elements in Object[] are the values you want:
lect player.age,count(player.ag e) from OBPlayer player");
List results = hibernateTemplate.find("se
for (int i = 0; i < results.size(); i++) {
Object[] result = (Object[])results.get(i);
BigDecimal age = (BigDecimal)result[0];
BigDecimal count = (BigDecimal)result[1];
}