Question

help with a regular expression

Asked by: anshuma

Hi,

I am passing the following argument
dateheader = "09/24/2009 15:16:32.099";
to the regular expression below

strsecond =  String.valueOf(dateheader.replaceAll(".+[\\ ]+([0-9]{1,2}):([0-9]*):([0-9]*):(.+)","$3"));

so that I can get the seconds in this case the answer should be 32. But I am getting the following output

09/24/2009 15:26:33.309

Could someone please fix the regular expression for me.

Also is there another cleaner way to handle dates. Like get the date part, year part , etc

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Asked On
2009-10-27 at 16:58:59ID24849344
Topic

Java Programming Language

Participating Experts
2
Points
500
Comments
9

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Answers

 

by: CEHJPosted on 2009-10-27 at 17:00:55ID: 25678920

>>Also is there another cleaner way to handle dates. Like get the date part, year part , etc

Yes. Use a DateFormat to set the Date on a Calendar

 

by: CEHJPosted on 2009-10-27 at 17:05:03ID: 25678936

Anyway, to get the atoms with a regex, you need split, not replaceAll:

String[] atoms = dateheader.split("[.:/ ]");

 

by: CEHJPosted on 2009-10-27 at 17:06:09ID: 25678944

(and then of course your seconds are atoms[atoms.length - 2]

 

by: anshumaPosted on 2009-10-27 at 17:09:06ID: 25678956

Hi CEHJ,

Could you please give me the whole regex. While I explore the datepart funcitonality. I don't know regex and I got this as maintenance work :-(

thanks
-anshu

 

by: objectsPosted on 2009-10-27 at 17:09:55ID: 25678964

 

by: CEHJPosted on 2009-10-27 at 17:21:37ID: 25679018

I'm really unclear as to why you want to replaceAll - it's the worst solution, but:

dateheader = dateheader(".*:(\\d+).*", "$1");

 

by: CEHJPosted on 2009-10-27 at 17:22:29ID: 25679021

Oops

dateheader = dateheader.replaceAll(".*:(\\d+).*", "$1");

 

by: anshumaPosted on 2009-11-01 at 23:06:55ID: 31646742

both of you are god

 

by: CEHJPosted on 2009-11-02 at 00:43:25ID: 25717825

:-)

20120131-EE-VQP-002

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