Question

LinkedList

Asked by: alepru

Hello. I need help writing a program that reads in a series of first names and stores them in a LinkedList. Do not store duplicate names. Allow the user to search for a first name.
This is what i have so far. Thank you.


import java.io.*;
import java.util.ListIterator;
import java.util.LinkedList;

public class llist
{
      public static void main(String[] args)throws IOException
      {
            BufferedReader dataIn=new BufferedReader(new InputStreamReader(System.in));
            //create LinkedList object
            LinkedList lList = new LinkedList();
            String names="";
            String response="";

            System.out.print("");
            System.out.print("Input a name:");
            names = dataIn.readLine();

            System.out.print("Would you like to enter another name? Enter yes or press any key to exit.");
            response = dataIn.readLine();
            if (response != null)
            {
                  response = response.toUpperCase();
            }

            while (response != null && response.equals("YES"))
            {
                  //add elements to LinkedList
                  lList.add(names);

                  System.out.print("Input name:");
                  names = dataIn.readLine();
                  System.out.print("Would you like to enter another name? Enter yes or press any key to exit.");
                  response = dataIn.readLine();
                  if (response != null)
                  {
                        response = response.toUpperCase();
                  }
            }

            lList.add(names);

            ListIterator itr = lList.listIterator();

            System.out.println("");
            System.out.println("This is the list of names entered:");

            while(itr.hasNext())
            {
                  System.out.println(itr.next());
            }

            System.out.println("");

      }

}

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Asked On
2009-11-03 at 21:58:39ID24869881
Topic

Java Programming Language

Participating Experts
4
Points
500
Comments
16

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Answers

 

by: a_bPosted on 2009-11-03 at 22:10:41ID: 25736825

This section looks a little suspect --

 while (response != null && response.equals("YES"))
            {
                  //add elements to LinkedList
                  lList.add(names); // You are adding before taking the input --Not required here

                  System.out.print("Input name:");
                  names = dataIn.readLine();
                  System.out.print("Would you like to enter another name? Enter yes or press any key to exit.");
                  response = dataIn.readLine();
                  if (response != null)
                  {
                        response = response.toUpperCase();
                  }
            }


 

by: mmseng4Posted on 2009-11-03 at 22:14:23ID: 25736845

Looks good so far. You can use a do-while loop to cut out a bit of code.

Does that work? Am I correct in assuming you just need to add the duplication check?

 

by: a_bPosted on 2009-11-03 at 22:15:00ID: 25736847

Algo -

response = "YES"
while(response != null && response.equals("YES"))
{
     -> read the data for the first time
        System.out.print("Input name:");
                  names = dataIn.readLine();
    -> ask question for response
}

That should do the trick.

What have you done so far for the search??

 

by: gurvinder372Posted on 2009-11-03 at 22:42:12ID: 25736960

You can first store these values in HashSet and then in Linked List.
HashSet automatically removes the duplicate values, so you won't be required to write a code to remove the duplicacy.

Let me know if this helps

 

by: CEHJPosted on 2009-11-04 at 00:04:14ID: 25737263

You can use

while (response != null && response.equalsIgnoreCase("YES"))

although it's perhaps slightly clunky to keep requiring YES. Ask them to enter 0 when they've finished or something.

To avoid duplicates, use

if (!IList.contains(names)) {
      IList.add(names);
}

although 'name' would be a better name here. btw, java variable names should begin lower case. Something like the following would be better:

if (!names.contains(name)) {
      names.add(name);
}

 

by: alepruPosted on 2009-11-04 at 16:11:51ID: 25745578

How do i do the search method and its still allowing duplicate names. thanks

 

by: gurvinder372Posted on 2009-11-04 at 23:37:10ID: 25747408

alepru: As suggested above, in my earlier post, you can use HashSet (from Java Collection Framework) to store the values first (you can convert into lowercase if the you don't want case-insensitive duplicacy).

Being the subset of Set class (interface), one of the HashSet property is to remove the duplicate elements. This process of removing the duplicacy happens as and when you are adding elements into the Hashset.

Let me know if using HashSet is not an option

 

by: a_bPosted on 2009-11-05 at 01:42:23ID: 25747896

You could also use a ArrayList and check whether the object is already there using the contains() method to check for duplicates.

 

by: CEHJPosted on 2009-11-05 at 03:06:32ID: 25748282

>>How do i do the search method and its still allowing duplicate names. thanks

Did you use the code i gave you at http:#25737263 ?

To search, use

int index = names.indexOf("foo");
if  (index > -1) {
    // found!
}

 

by: alepruPosted on 2009-11-05 at 08:47:43ID: 25751349

Savant,
Thank You..I have used both codes, they both work. The only problem now is that it won't show me the list off all the names entered. It just shows the last name entered.

 

by: CEHJPosted on 2009-11-05 at 08:50:00ID: 25751378

Please post the code you're currently running

 

by: alepruPosted on 2009-11-05 at 09:56:53ID: 25752055

import java.io.*;
import java.util.ListIterator;
import java.util.LinkedList;

public class llist
{
      public static void main(String[] args)throws IOException
      {
            BufferedReader dataIn=new BufferedReader(new InputStreamReader(System.in));
            //create LinkedList object
            LinkedList lList = new LinkedList();
            String names="";
            String response="";

            System.out.print("");
            System.out.print("Input a name:");
            names = dataIn.readLine();

            System.out.print("Would you like to enter another name? Enter yes or press any key to exit.");
            response = dataIn.readLine();
            if (response != null)
            {
                  response = response.toUpperCase();
            }

            while (response != null && response.equals("YES"))
            {


                  System.out.print("Input name:");
                  names = dataIn.readLine();
                  System.out.print("Would you like to enter another name? Enter yes or press any key to exit.");
                  response = dataIn.readLine();
                  if (response != null)
                  {
                        response = response.toUpperCase();
                  }
            }

            if (lList.contains(names))
            {
                  lList.add(names);
            }

            int index = names.indexOf("Aleona, Alex, Emilie, Johnny");
            if  (index > -1)
            {
                // found!
            }


            System.out.println("This is the list of names entered:");
            System.out.println("");


            lList.add(names);
            ListIterator itr = lList.listIterator();

            while(itr.hasNext())
            {
                  System.out.println(itr.next());
            }

            System.out.println("");

      }

}

 

by: a_bPosted on 2009-11-05 at 09:58:40ID: 25752072

while (response != null && response.equals("YES"))
            {


                  System.out.print("Input name:");
                  names = dataIn.readLine();
              if (lList.contains(names)==false)
            {
                  lList.add(names);
            }
                  System.out.print("Would you like to enter another name? Enter yes or press any key to exit.");
                  response = dataIn.readLine();
                  if (response != null)
                  {
                        response = response.toUpperCase();
                  }
            }

         

 

by: CEHJPosted on 2009-11-05 at 12:41:11ID: 25753773

Using what i mentioned earlier:

	System.out.println("Enter each name on a separate line or 0 to quit");
	String name = null;
	while((name = dataIn.readLine()) != null && name.indexOf("0") < 0) {
	    names.add(name.trim());
	}
	// Done!
                                              
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by: alepruPosted on 2009-11-20 at 12:50:43ID: 25874420

ok thank you

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