Question

C Math functions in RPGIV and floating point variables

Asked by: kfpetmart

I'm trying to write a program that computes the distances between 2 points using the 'great circle distance' formula.  I'm using the C - ACOS function and my variables are defined as '8f' floating point.

This is the first time I've tried to do higher math functions in RPG and the first time with float point variables.  I've searched the Internet and found many examples and have used them but cannot get the expected result WHEN USING FLOATING POINT variables.  All the examples use floating point variables.  I get a somewhat close result when I use signed decimal variables.

Is there some rule I don't know about when using floating point variables?  I have the 'FLTDIV' H-statement at the top of my program.  

Thanks.

Kevin

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Asked On
2009-11-05 at 09:09:04ID24875177
Topics

RPG Programming Language

,

Programming for iSeries / AS400

Participating Experts
2
Points
500
Comments
7

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Answers

 

by: Gary_The_IT_ProPosted on 2009-11-05 at 22:40:41ID: 25757073

Please post a code sample and actual and expected results.

- Gary Patterson

 

by: kfpetmartPosted on 2009-11-06 at 06:53:54ID: 25759581

This is how I coded from examples on the Internet.  Everything using floating point variables.

Data:

Latitude 1 (LATCPZ): 41.320612

Longitude 1 (LNGCPZ): -81.363520

Latitude 2 (LATCSE): 39.6263358

Longitude 2 (LNGCSE): -84.1956464

Code Example:

D ACos            PR             8F   ExtProc('acos')    
D  ACRadians                     8F   Const              
D Cos             PR             8F   ExtProc('cos')    
D  CRadians                      8F   Const              
D Sin             PR             8F   ExtProc('sin')    
D  SRadians                      8F   Const  

D RLat1           S              8f
D RLat2           S              8f
D RLng1           S              8f
D RLng2           S              8f

D a               S              8f  
D b               S              8f  
D c               S              8f  

c                   Eval      RLat1 = LatCpZ/57.2958                  
c                   Eval      RLng1 = LngCpZ/57.2958                  
c                   Eval      RLat2 = LatCSe/57.2958                  
c                   Eval      RLng2 = LngCSe/57.2958                  
                                                                       
* Calculate distance between locations and convert to miles          
c                   Eval      a = ACos((Sin(RLat1)*Sin(RLat2)) +      
c                             (Cos(RLat1)*Cos(RLat2)*Cos(RLng2-RLng1)))
c                   Eval      b = a * 6371.01                          
c                   Eval      c = b * .62137                            

Expected Result:            188.9 miles

Actual Result:                   3.1067 miles  

 

 

by: Gary_The_IT_ProPosted on 2009-11-09 at 12:30:25ID: 25779695

Well, without testing (and assuming you have the formula right, and it looks good at a quick glance), there are two likely candidates.

First of all, floating point numeric values are compromises that allow us to represent approximations of numbers in a relatively compact form.  Floating points aren't great when you need a lot of precision, since less-significant digits get lopped off. You're using double-precision floating points here, which give you the ability to approximate some very large and small numbers, but won't give you the precision of large decimal formats for numbers in the restricted ranges that you need here.

Second, the implementation that you have chosen is apparently sensitive to rounding errors, especially at small distances.  You might want to consider trying the Haversine formula, or the somewhat more complex special case of the Vincenty formula:

http://en.wikipedia.org/wiki/Great-circle_distance

- Gary Patterson

Check out my EE profile:  http://www.experts-exchange.com/M_4382324.html

 

by: tliottaPosted on 2009-11-09 at 14:57:51ID: 25781011

BTW, what are the definitions of the CpZ and CSe variables? Also, I don't think I'd break the formula into three separate a, b and c components. Each one separately probably introduces additional conversion/precision errors. Use a single unified formula. And that probably could be applied to the constants too -- provide them with declared data types, most likely 8F for each of them.

Tom

 

by: kfpetmartPosted on 2009-11-10 at 07:11:57ID: 25786115

thanks.  I'll give both suggestions a try.

 

by: Gary_The_IT_ProPosted on 2009-11-10 at 11:28:38ID: 25788810

I finally had time to compile it and run it under debug.  Problem was quickly apparent when I broke the formula down into multiple steps.

The trig functions are returning unpredictable values becuase parms are being passed incorrectly.

These C-library functions receive parameters by VALUE, not reference.

Specifying CONST causes a REFERENCE (pointer) to a COPY of the original parameter to be passed, in effect making the original parameter read-only.  This is bad, since the function is expecting to receive a double-precision floating point VALUE, not a pointer.

Change your CONST keywords to VALUE, and all should be good (unless the accuracy thing is a problem for you, then you might want to also consider using an alternate formula).

- Gary Patterson

 

by: kfpetmartPosted on 2009-11-11 at 06:17:46ID: 31650598

Excellent!  Much closer.  It was about 1 mile different than a tool I found on the web but I'll take it.  Thanks for your help Gary.

20120131-EE-VQP-002

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