Question

Return number ofdays and hours between date

Asked by: Etho

we need an function to returno number of hours (abouve 24 hours) using TDateTime

Sample:

dt_1: TDateTime;
dt_2: TDateTime;

dt_1 := StrToDateTime('12/28/2009 00:00');
dt_2 := StrToDateTime('12/30/2009 13:15');

dt_2 - dt_1 = return 3 days and 1 hours and 15 minutes

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Asked On
2009-11-03 at 09:22:02ID24867937
Tags

delphi

,

vcl

Topics

Delphi Components

,

Delphi IDE

,

Delphi Database

Participating Experts
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Points
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Comments
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Answers

 

by: rfwoolfPosted on 2009-11-03 at 09:30:31ID: 25731329

Add Dateutils unit to your uses list

Use Daysbetween,
Hours between,
Minutesbetween functions

or look at the Dateutils methods list in the help file for a full list of date and time handling functions

 

by: epasquierPosted on 2009-11-03 at 09:39:29ID: 25731431

Is that not about the same question you just closed ?

if you want to have the nb of days, hours, min you can use

procedure DecodeDate(Date: TDateTime; var Year, Month, Day: Word);

in SysUtils

var Year, Month, Day: Word;
begin
 DecodeDate(dt_2 - dt_1, Year, Month, Day );
end;

                                              
1:
2:
3:
4:

Select allOpen in new window

 

by: Geert_GruwezPosted on 2009-11-03 at 11:00:51ID: 25732239

etho
you need to post remarks if you don't understand something

this is a 2 way process: asking, answering and commenting ...

 

by: epasquierPosted on 2009-11-06 at 08:38:22ID: 25760647

Ah, actually by looking again at this thread, I see that what you need is not exactly DecodeDate but

DecodeDateTime(const AValue: TDateTime; out AYear: Word; out AMonth: Word; out ADay: Word; out AHour: Word; out AMinute: Word; out ASecond: Word; out AMilliSecond: Word);

Var
 Year, Month, Day: Word;
 Hour, Min, Sec, MilSec: Word;
begin
 DecodeDateTime( dt_2 - dt_1, Year, Month, Day, Hour, Min, Sec, MilSec );
end;

Or DecodeTime + nb of full days not decoded (=8 if 1week+1day) :

Var
 Days: Word;
 Hour, Min, Sec, MilSec: Word;
begin
 DecodeDateTime( dt_2 - dt_1, Hour, Min, Sec, MilSec );
 Days:=Trunc( dt_2-dt_1);
end;

Now you have about all possible solutions, choose the best suited for your needs

 

by: epasquierPosted on 2009-11-06 at 08:39:45ID: 25760665

hum, error on the last, of course it's not DecodeDateTime but DecodeTime. This post editor is too small to be usable.... And this is end of week ;o)

Var
 Days: Word;
 Hour, Min, Sec, MilSec: Word;
begin
 DecodeTime( dt_2 - dt_1, Hour, Min, Sec, MilSec );
 Days:=Trunc( dt_2-dt_1);
end;

 

by: tormorkPosted on 2009-11-07 at 16:19:32ID: 25768773

A TDateTime is the number of days since some date (can't remember what date but that is not important)

So i you have two TDateTime d1 and d2 the number of days between them is Trunc(d2-d1)
what is left (ie frac(d2-d1)  is the number hours:min...
The fractional part represent the time,
So if f = frac(d2-d1) you have:

Hours = trunc(f*24)
Minutes = trunc(f*24*60)-Hours*60
Seconds = trunc(f*24*60)-Hours*60-Minutes*60*60

I have assumed that d2 is larger than d1, if not you can swap them and then use the above.

By the way if you just want to display the difference you can also use IntToStr(trunc(d2-d1) + " days " + TimeToString(d2-d1)
(I think it was called TimeToString but something like that) again d2 should be larger than d1.

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