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7.0

Checking to see if user is part of an active direcory group..

Asked by rhawk in Delphi Programming, Microsoft Programming

Tags: Delphi

I am trying to check and see if the user running the program is a member of a group in Active Directory.
Using the units ActiveDs_TLB and adshelp I have come up with a function that does check if a user is in a group. The probem is that the user must be directly in the group. If the user is part of another group thatis part of the group then the user is not found. I realize I need to locate all groups under the main group and check them for users AND more groups, but the problem is I cannot seem to figure out how.

Here is the routine I have so far (there is a showmessage in it that displays the users names it finds for debugging)., Pardon it being a bit sloppy but it is a work in progress.

(This question continues so I can post 1 more code example)
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function GroupMember(sGroup: String): Boolean;
var
   sUser,
   	sCall	: string;
   oUser		: IADsGroup;//IADsContainer;
   grp 		: IAdsUser;
   grps 		: IAdsMembers;
   Enum		: IEnumVariant;
   varGroup : OleVariant;
   Temp 		: LongWord;
   bMatch	: boolean;
 
begin
   sUser := ReplaceText(getUserNameEx(2), 'ste\', '');
	sCall := 'WinNT://ste/' + sGroup + ',group';
	ADsGetObject(sCall, IADsGroup, oUser);
   grps:=oUser.Members;
   bMatch := false;
     Enum := grps._NewEnum as IEnumVariant;
 
  if Enum <> nil then
    while (NOT bMatch) AND (Enum.Next(1,varGroup, Temp) = S_OK) do begin
      grp := IDispatch(varGroup) as IAdsUser;
      bMatch :=  SameText(grp.Name, sUser);
      showmessage(grp.Name);
      VariantClear(varGroup);
    end;
  result:=bM
[+][-]04/08/08 10:51 AM, ID: 21307762Accepted Solution

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About this solution

Zones: Delphi Programming, Microsoft Programming
Tags: Delphi
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Solution Provided By: rhawk
Participating Experts: 1
Solution Grade: A
 
[+][-]04/04/08 10:25 AM, ID: 21283843Author Comment

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[+][-]04/04/08 01:12 PM, ID: 21285279Expert Comment

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[+][-]04/04/08 03:04 PM, ID: 21285954Author Comment

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[+][-]04/04/08 03:58 PM, ID: 21286257Expert Comment

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[+][-]04/07/08 06:34 AM, ID: 21296676Author Comment

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[+][-]04/07/08 07:58 PM, ID: 21302235Expert Comment

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