Advertisement

03.01.2008 at 07:53AM PST, ID: 23206221
[x]
Attachment Details
[x]
The Solution Rating System

With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.

  • The Grade of the Solution
  • The Zone Rank of the Expert Providing the Solution
  • The Number of Author and Expert Comments
  • The Number of Experts Contributing
  • The Feedback of the Community

Your Input Matters
Because of the way the system is set up, the most important variable in this equation is you. As a member of Experts Exchange, you are able to cast your vote on the quality of the solutions in regard to how complete, accurate, helpful and easy to understand each solution is. When you provide your feedback, each rating is adjusted accordingly. So, if you see a solution that has a poor rating that you think is a good solution, let us know by rating it. As you do, the rating will be adjusted and will become more accurate for other members of our site.

If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support.

Thank you!

Building a 2D array

Tags: Perl
Hello,
I 'm trying to build a 2D array from witin my code. So I want to have an array @list that holds arrays @info.
first I declare my @list and my @info
While reading from a file, I read line per line and build for each line a line @info using the split function
sub PopulateArray
{
    @list= undef;
    my $cntr = 0;
    # populate array
    open TXT, "<$root/$section/cfg/$fileTXT" or die "not found $!\n";
    while (<TXT>)    {
        unless (m/^\s*$/)  {
            chomp;
            @info = split(/ = /, $_);
            # add a - to array
            push @info, "-";
            # 0: host, 1: volume = target, 2: oid  3: -
            $list[$cntr] = @info;
            $cntr++;
        }
    }
    close TXT;
}

The above seems to give me an array @list with all '4' in it.
I tried push @list, @info but I figured out that this only give me a 1D array with all info found. Not what I want.

So, how can I build pu an array @list by adding  @info stuff so I can get it back by using a simple reference like  $list[0][3]  or $list[12][2] etc.

thx in advance





I build up

Start your free trial to view this solution
Question Stats
Zone: Programming
Question Asked By: Marc_Engrie
Solution Provided By: mjcoyne
Participating Experts: 1
Solution Grade: A
Views: 38
Translate:
Loading Advertisement...
03.01.2008 at 08:04AM PST, ID: 21022154

Rank: Sage

All comments and solutions are available to Premium Service Members only.

Start your 7-day free trial and see for yourself why Experts Exchange is the easiest and most proven technology resource in the world. Get Started

Already a member? Login to view this solution.

 
 
Loading Advertisement...
20080236-EE-VQP-29 / EE_QW_2_20070628