July 24, 2008 04:01am pdt

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04.16.2008 at 12:31AM PDT, ID: 23326189

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9.4

Pattern Matching Syntax Help Needed

Zones: Perl Programming Language, Regular Expressions

Tags: Perl, 5

I'm very new to perl and am looking for assistance on building a simple pattern matching program that runs a command on a linux box, stores the output in a variable, then based on a pattern matching if statement runs a subroutine. Here is what I am trying but it doesn't work for me:
------------------------------------------------------------
my $ACUSERVE = `/acu6/bin/acuserve -info`;
if ($ACUSERVE =~ /version/m) {
print "good";
&send_alert;
exit;
}
else {
print "bad";
&send_alert2;
}
----------------------------------------------------------------------
In this case I always get the "bad" print to initiate and never matches to get the "good". The command output is a multiline output that varies depending on status. the example is below of the output of the command:
0 file(s) in use by acuserve on: computer.domain.com (PID 5761)
Server Port: 6523, AcuServer version 6.0.0

So I want to match on say for example the pattern "version".

Your assistance is appreciated. The solution is probably a simple one for an experienced developer but due to the urgency of our needs I have assigned the appropriate points.

Thank you.

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Question Stats

Zone: Programming

Question Asked By: zarcow

Solution Provided By: Adam314

Participating Experts: 5

Solution Grade: A

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04.16.2008 at 12:45AM PDT, ID: 21365557

Rank: Genius

ozo:

Are you sure $ACUSERVE contains "0 file(s) in use by acuserve on: computer.domain.com (PID 5761)
Server Port: 6523, AcuServer version 6.0.0"

04.16.2008 at 04:45AM PDT, ID: 21366615

Rank: Master

nedfine:

can you just print $ACUSERVE and see if it contains the expected line ?

Thanks
Ned

04.16.2008 at 05:18AM PDT, ID: 21366873

amar_r:

If your response is failure of a command,the string $ACUSERVE will be empty.
Try printing the $ACUSERVE after executing the command.

I have tested your code by passng "ls -ltr" and "ls -zl".If the command is success,the code we will get a expected output otherwise no.

04.16.2008 at 06:56AM PDT, ID: 21367759

zarcow:

When I run my perl script without declaring a print statement for the $ACUSERVE variable it still prints it on screen, but when I put a print statement in, it will print it on screen only once as when there is no print statement. This leads me to believe that the $ACUSERVE variable is not retaining the output correctly as I would expect it to print on screen twice with the print statement in place. Am I declaring the variable correctly to get it to run as a command outside of perl?

04.16.2008 at 06:57AM PDT, ID: 21367768

zarcow:

In addition, it will just print "bad" on the else condition but not the $ACUSERVE output when I place a print $ACUSERVE above the print "bad" statement.

04.16.2008 at 07:00AM PDT, ID: 21367805

Rank: Master

nedfine:

it would better if you use system.
$var = system('command');

Thanks
Ned

04.16.2008 at 07:04AM PDT, ID: 21367838

zarcow:

One more thing, am I supposed to execute the $ACUSERVE command somehow aside from the way its setup in the code I posted above, and then print it?

04.16.2008 at 07:14AM PDT, ID: 21367954

Rank: Genius

Adam314:

The system command will not get the output in $var, you will only get the exit value.

It sounds like the acuserve program is not writing to STDOUT (which is what the backticks capture). If it is writing to STDERR, you could redirect that to STDOUT, so it can be captured:

                       
             my $ACUSERVE = `/acu6/bin/acuserve -info 2>&1`;
print "acuserve=$ACUSERVE\n";

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Accepted Solution

04.16.2008 at 07:18AM PDT, ID: 21367994

zarcow:

I tried using the system instead as recommended, here is how I declared it, please correct me if I'm wrong:

my $var = system(`/acu6/bin/acuserve -info`)
if ($var =~ /version/m) {
print "good";
print $var;
&send_alert;
exit;
}
else {
print "bad";
print $var;
&send_alert2;
}

Now what happens is that I do get an output to print for the $var variable but its not the expected output. I get a number that prints "65280" which I have no idea what it means or where its getting it from. When I execute the command above manually it always gives me the expected output and when executing the perl script it will first give me the expected output on the screen but after the if statement, the print statements there don't bring up the right output just the number mentioned.

04.16.2008 at 07:20AM PDT, ID: 21368020

Rank: Guru

ahoffmann:

> but not the $ACUSERVE
then this variable is empty, most likely 'cause the command did not return something

try to use:

$ACUSERVE = `/acu6/bin/acuserve -info 2>&1`;

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