|
[x]
Posted via EE Mobile
|
||
Search, ask, and monitor your questions on the go with EE Mobile. Visit Experts Exchange from your mobile device and never be out of touch again. |
||
| 09/23/2009 at 12:41PM PDT, ID: 24756284 |
|
[x]
Attachment Details
|
||
|
[x]
The Solution Rating System
|
||
With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.
Your Input Matters If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support. Thank you! |
||
1: 2: 3: 4: 5: 6: 7: 8: 9: 10: 11: 12: 13: 14: 15: 16: 17: 18: 19: 20: 21: 22: 23: 24: 25: 26: 27: 28: 29: 30: 31: 32: 33: 34: 35: 36: 37: 38: 39: 40: 41: |
import java.util.ArrayList;
import java.util.Iterator;
/*
* This code is to create two sets of Strings,
*two sets of Integers, and two sets of a user defined
* type(over ride the toString() method for display
*
*/
/**
*
* @author Kween2
*/
public class QueryInformation {
Iterator itorator;
public static void main(String[] args) {
ArrayList<String>listNames = new ArrayList<String>();
listNames.add("Royce");
listNames.add("Donna");
listNames.add("Feona");
//print the array list
for(int i = 0; i < listNames.size(); i++) {
String name = listNames.get(i);
System.out.println(name);
}
System.out.println("----- rpn----");
for ( String name : listNames ) {
System.out.println(name);
}
//using an element : collection to print the names a second time
Iterator<String>iterator=listNames.iterator();
while(listNames.hasNext()) {
System.out.println(listNames.next());
}
}
}
|
Advertisement
