Question

Positive decimal value regular expression with max 3 decimal places

Asked by: smacca

I need to update my regular expression so it has the following:

  * Accepts all positive decimal values (currently only accepts values greater and equal to one (1))
  * i.e accepts ---> 0.0001

  * Can have maximum 3 decimal places.
  * Decimal places are optional.


This regular expression will be used to validate currency input.

ValidationExpression="^\d*[1-9]\d*(\.\d+)?$"

                                  
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Asked On
2008-01-05 at 19:48:11ID23061549
Tags

C#

Topics

Regular Expressions

,

.NET

,

C# Programming Language

Participating Experts
2
Points
500
Comments
11

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Answers

 

by: gnoonPosted on 2008-01-05 at 21:16:39ID: 20592686

^[1-9]\d*(\.\d{1,3})?$

 

by: ozoPosted on 2008-01-05 at 21:35:57ID: 20592760

^(?=\d*(\.\d{1,3})?$)(?=.*[1-9])

 

by: gnoonPosted on 2008-01-05 at 22:35:13ID: 20592990

Ah .. my comment above I was misunderstood to accept only values greater than 0 ;)
Please ignore it.

 

by: smaccaPosted on 2008-01-06 at 04:29:48ID: 20593666

None of the above solutions work. Have you guys tested??

 

by: gnoonPosted on 2008-01-06 at 05:31:22ID: 20593857

I'm just confused. You said that "Can have maximum 3 decimal places", but why accepts 0.0001. It's 4 decimal places. To accept it (4 decimal), just use ozo's regex but change from \d{1,3} to \d{1,4}

Here output of code below (I modified the regex a bit from ozo)

[123]           = 123 (True)            parse = success
[  123  ]       = 123 (True)            parse = success
[01.1234]       = 1.1234 (True)         parse = success
[1.1234]        = 1.1234 (True)         parse = success
[-1.123]        = -1.123 (False)        parse = success
[-0.0]          = 0.0 (False)           parse = success
[0.0]           = 0.0 (True)            parse = success
[00.0]          = 0.0 (True)            parse = success
[.0001]         = 0.0001 (True)         parse = success
[0.0001]        = 0.0001 (True)         parse = success
[a0.0001]       = # (False)             parse = failed
[ ]                   = # (False)             parse = failed

            string[] test = {
                                "123",
                                " 123.0 ",
                                "01.1234",
                                "1.1234",
                                "-1.123",
                                "-0.0",
                                "0.0",
                                "00.0",
                                ".0001",
                                "0.0001",
                                "a0.0001",
                                " a"
                            };
            Regex rx = new Regex(@"^\s*(?=\d*(\.\d{1,4})?\s*$)(?=.*[0-9])");
            foreach (string s in test)
            {
                Console.Write("["+s+"] \t= ");
                string ps = "success", d = "#";
                try { d = Decimal.Parse(s).ToString(); } catch (Exception) { ps = "failed"; }
                Console.WriteLine(d+" ("+rx.IsMatch(s)+")\t\tparse = "+ps);
            }

                                              
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by: smaccaPosted on 2008-01-07 at 17:54:36ID: 20605308

Still not working for some reason - I understand your code works fine but it doesnt translate to my example. Can you have a look at the code below:

<%@ Page Language="C#" AutoEventWireup="true"  CodeFile="Default.aspx.cs" Inherits="_Default" %>
 
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
 
<html xmlns="http://www.w3.org/1999/xhtml" >
<head runat="server">
    <title>Untitled Page</title>
</head>
<body>
    <form id="form1" runat="server">
    <div>
    
    
    <asp:TextBox ID="txtTest" Width="250" runat="server" />
    
    <asp:RegularExpressionValidator Enabled="true" ID="revPositiveCurrency" ControlToValidate="txtTest" Display="None" ErrorMessage="Positive decimal currency only!" ValidationExpression="^\s*(?=\d*(\.\d{1,4})?\s*$)(?=.*[0-9])" runat="server" /
    
    <asp:Button ID="btnSubmit" Text="SUBMIT" runat="server" />
    <asp:ValidationSummary ID="vsSummary" DisplayMode="BulletList" ShowSummary="true" HeaderText="Errors:" runat="server" />
    
    </div>
    </form>
</body>
</html>
                                              
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by: ozoPosted on 2008-01-07 at 17:59:08ID: 20605349

do you need \\ in quotes

 

by: smaccaPosted on 2008-01-07 at 18:02:16ID: 20605373

You will likely need \\ in the quotes. Your code uses "@" to make the statement a literal syntax meaning you do not have to \\ things etc. I will try out now and get back to you.

 

by: smaccaPosted on 2008-01-07 at 18:04:46ID: 20605381

Cannot sort out myself - I do not know what to \\ in the statement. If you have IIS, you can test the page I provided very easily. Thanks for your help!

 

by: gnoonPosted on 2008-01-07 at 20:18:50ID: 20605940

After deeply dig, I found that it's limitation of javascript function (RegularExpressionValidatorEvaluateIsValid) in WebUIValidation.js, and all regex above won't work.

The first group of matching result must equal to the whole value of the element, and the only one I can get now is

ValidationExpression="^\s*\d+(\.\d{1,4})?\s*$"

which is not cover all valid decimal values e.g. .0001 (but accept 0.0001). I think, this is acceptable.

 

by: smaccaPosted on 2008-01-29 at 22:41:46ID: 31419275

No exact answer provided.

20120131-EE-VQP-002

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