Question

regex for compliment

Asked by: eyeqube

Hi,

      I have a string "Matches any character except a newline". Is it possible to match every other part of this string except "a newline". In other words I need to cut "a newline" and take only the first part of it. How is it possible

BRgds,

kNish

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Asked On
2008-11-13 at 21:49:32ID23904367
Tags

python

,

2.5

,

regular expression

Topics

Regular Expressions

,

Python Scripting Language

Participating Experts
5
Points
500
Comments
8

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Answers

 

by: ozoPosted on 2008-11-13 at 22:10:36ID: 22957560

(.*)a newline

 

by: b0lsc0ttPosted on 2008-11-13 at 22:33:05ID: 22957618

eyeqube,

If you dot character is matching the newline character and you using this in Python make sure you don't have the DOTALL flag in your expression.  The default is the character won't match a newline but that flag can change it.  If I have misunderstood what you asked then let me know.

Let me know if you have any questions or need more information.

b0lsc0tt

 

by: eyequbePosted on 2008-11-13 at 23:37:58ID: 22957806

Hi,

     I tried ozo's suggestion. It does not give me the desired result. let me explain my question again in other words.

   I have a string that has extra information. "//abcd-999/beeHive/hexagon/honey/sugar/honey". This string has the last two folder names "/sugar/honey". I need to have only "//abcd-999/beeHive/hexagon/honey" part stored.

BRgds,

kNish

 

by: ddrudikPosted on 2008-11-14 at 00:23:48ID: 22957935

It seems the string in the original question was misinterpreted, it appears that was just an example string and not meant to be interepreted as a . matches \n question.

It depends on your rules for matching "/sugar/honey" but if it is literal:

re.sub("/sugar/honey$", "", subject)

                                              
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by: peprPosted on 2008-11-14 at 06:51:08ID: 22959915

It depends on what you really want. But such cases can usually be better solved without regular expressions. It depends what exactly should be removed/replaced. You should clarify your intention better.

Try the snippet below to see how the string can be split by '/', the resulting list modified or extracted and then the other list joined again into a string.

s1 = '//abcd-999/beeHive/hexagon/honey/sugar/honey'
print repr(s1)
 
lst = s1.split('/')
print lst
 
s2 = '/'.join(lst)
print repr(s2)
 
# One possible manipulation.
lst2 = lst[0:5] + lst[-1:]
print lst2
 
s3 = '/'.join(lst2)
print repr(s3)
                                              
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by: peprPosted on 2008-11-14 at 06:51:52ID: 22959921

The above prints the output...

'//abcd-999/beeHive/hexagon/honey/sugar/honey'
['', '', 'abcd-999', 'beeHive', 'hexagon', 'honey', 'sugar', 'honey']
'//abcd-999/beeHive/hexagon/honey/sugar/honey'
['', '', 'abcd-999', 'beeHive', 'hexagon', 'honey']
'//abcd-999/beeHive/hexagon/honey'

 

by: peprPosted on 2008-11-15 at 08:48:01ID: 22967750

Well, it was a little joke ;) The lst2 assignment command was to be...

lst2 = lst[:-2]   # i.e. copy the lst form the beginning except the last two elements

 

by: jdpipePosted on 2008-11-19 at 22:53:27ID: 23001676

is this what you're looking for?



>>> s = "hello\nthis is the rest"
>>> print "'%s'" % s.split("\n",1)[0]
'hello'

                                              
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