Question

Detect patterns existing in multlple strings or sentences

Asked by: guyneo

Hi,
I am trying to recognize patterns. Given a input of multiple sentences, the program needs to detect if there are any recurring patterns of words (or groups of words) in them.   The program does not have a set of patterns to begin searching with. It is just supposed to detect any and all  patterns that exist in more than one sentence.
I really appreciate your help Guys
thanks

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Asked On
2009-03-26 at 13:09:50ID24268971
Tags

java regex string pattern detect

Topics

Regular Expressions

,

New to Java Programming

Participating Experts
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Points
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Comments
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Answers

 

by: javaexpertoPosted on 2009-03-26 at 14:24:14ID: 23995495

In java you can use Pattern and Matcher classes.

With Pattern class you stablish your pattern that u'll look for. With Matcher class you pass your input or string where the patterns are.

For example in the code below, you are looking for the pattern a*b, that's means cero or mora 'a' followed by one b.

The String you look for that pattern is "aaaaab". Finally you ask with Matcher object if there is any pattern and save the result into a boolean.

If you want the words instead of just know if there is a pattern, then u can use split method from String class, it method will return an array with the "words" matched in your string, for example

String s = "aaaaab"

String arrayResult[] = s.split("a*b")

Pattern p = Pattern.compile("a*b");
Matcher m = p.matcher("aaaaab");
boolean b = m.matches();

                                              
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by: javaexpertoPosted on 2009-03-26 at 14:41:25ID: 23995708

I think I got u, you wont stablish the pattern in the beginning. But how do u know what would be a pattern? For example the first sentence

aaa bbb cc

the second

aa bb bcc

In this case would you say that the first pattern is aa? or bbb?

What I want to tell is that you need to define for example if the blank space will be part of the pattern.

 

by: guyneoPosted on 2009-04-01 at 07:55:43ID: 24039821

Sorry. I should have given examples to make it more clear.
you are right.  

I would say any group of consecutive words (including the space or , etc) can be considered a possible pattern.

Say I have 5 groups of words as input.
Say 1st group of words is :  bb asc ddd vhjk jksdjk lddsd
Say 2nd group of words is :  vhjk jksdjk lddsd
Say 3rd group of words is :  khjsd jhjksd jkhsd ui jkhkd
Say 4th group of words is :  bb asc ddd vhjk jksdjk lddsd jik hsd bn

I like to take group 1, and make a list of possible patterns (groups of cosecutive words)
bb asc ddd vhjk jksdjk lddsd
bb asc ddd vhjk jksdjk
bb asc ddd vhjk
bb asc ddd
bb asc

asc ddd vhjk jksdjk lddsd
asc ddd vhjk jksdjk
asc ddd vhjk
asc ddd

ddd vhjk jksdjk lddsd
ddd vhjk jksdjk
ddd vhjk
 
vhjk jksdjk lddsd
vhjk jksdjk

jksdjk lddsd

And detect occurrences of these in the other groups. then I repeat the same process with other groups

On the face of it, it looks like just string matching might work but I like to check with people who have experience with regular expressions if its the best way to go.   I would be grateful for any other suggestions to do this in a more efficient way : coding wise and performance wise

 

by: javaexpertoPosted on 2009-04-07 at 10:52:14ID: 24089998

You can use the split method of String class. split receives the regular expression to match in a given String. For example:

String s will be the groups where you will search, and String g into split method will be your group that will reduce its size. So my advice is that you use StringTokenizer to separate your String g in order to pass all the patterns to split method:

bb asc ddd vhjk jksdjk lddsd
bb asc ddd vhjk jksdjk
bb asc ddd vhjk
bb asc ddd
bb asc

String s = "vhjk jksdjk lddsd"; // the group
String g = "bb asc ddd vhjk jksdjk lddsd" //the pattern
String []arrayResult = s.split(g);

                                              
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by: guyneoPosted on 2009-04-14 at 07:09:45ID: 24138340

I will try this out. I am hoping it will work.

 

by: guyneoPosted on 2009-09-17 at 10:00:16ID: 25358399

Actually it looks like we have to repeat the whole process again to  actually see if there are any patterns.

20120131-EE-VQP-002

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