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9.1

RegEx: Split by non-word char, except inside quotes

Asked by headzoo in Regular Expressions, C Programming Language, C++ Programming Language

Tags: regex, boost, c++

Hi,
Been banging my head on this one for a little while. I'm using boost::regex, and I'd like to split a string by non-word characters, except where the non-word character is inside quotes.

An example string:

The gopher's bike wasn't "hot enough" for the judges.

Would get split into:

The
gopher
'
s
bike
wasn
'
t
"hot enough"
for
the
judges
.
The really tricky part is where the quoted string has an escaped quote. For example:

Here is a "string with \"a quote\" inside" of it.

That should be split as

Here
is
a
"string with \"a quote\" inside"
of
it
.
I think boost::regex is Perl compatible, so it shouldn't matter if I'm using boost::regex, or PHP's preg_split, or any other Perl compatible regex engine.

Can anyone offer any suggestions?

P.S. Yes, I'm trying to keep the quotes in the match, as the split examples above show.
[+][-]05/20/09 07:16 AM, ID: 24432078Expert Comment

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[+][-]05/20/09 07:52 AM, ID: 24432528Expert Comment

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[+][-]05/20/09 07:57 AM, ID: 24432594Accepted Solution

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About this solution

Zones: Regular Expressions, C Programming Language, C++ Programming Language
Tags: regex, boost, c++
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Solution Provided By: ddrudik
Participating Experts: 2
Solution Grade: A
 
[+][-]05/20/09 01:58 PM, ID: 24436251Expert Comment

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