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04.03.2008 at 08:16AM PDT, ID: 23293085
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7.3

Get all records group by id and last update date

Asked by spgaddipati in SQL Query Syntax, Databases Miscellaneous, MS SQL Server

Tags:

How to get the last update user for each review id for the following table date.
Id               rev_id          createuser            create date
19      2      27      8/29/06 1:52 PM
72      2      25      9/13/06 2:40 PM
32      2      71      9/8/06 9:28 AM
33      2      71      9/8/06 9:28 AM
20      2      27      8/29/06 1:54 PM
41      2      71      9/12/06 11:32 AM
79      2      71      9/14/06 9:53 AM
80      2      71      9/14/06 9:54 AM
6      2      53      8/28/06 8:56 AM
11      5      53      8/28/06 12:48 PM
93      5      71      9/15/06 3:08 PM
92      5      71      9/15/06 3:07 PM
91      5      71      9/15/06 3:06 PM
12      5      53      8/28/06 1:19 PM
24      7      53      8/30/06 8:13 AM
95      7      71      9/15/06 4:00 PM
96      7      71      9/15/06 4:15 PM
87      7      71      9/15/06 10:58 AM
35      7      71      9/8/06 2:07 PM
25      7      54      8/30/06 8:48 AM
26      7      54      8/30/06 8:50 AM
52      7      71      9/12/06 4:25 PM
97      7      71      9/15/06 4:16 PM
98      7      71      9/15/06 4:16 PM
27      7      54      8/30/06 9:09 AM
23      7      53      8/30/06 8:05 AM
30      8      71      9/7/06 5:19 PM
39      8      71      9/12/06 11:27 AM
40      8      71      9/12/06 11:29 AM
38      8      71      9/12/06 11:24 AM
31      8      71      9/7/06 5:42 PM


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[+][-]04.03.2008 at 08:30AM PDT, ID: 21273671

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Zones: SQL Query Syntax, Databases Miscellaneous, MS SQL Server
Tags: sql
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Solution Provided By: jogos
Participating Experts: 3
Solution Grade: A
 
 
[+][-]04.03.2008 at 10:20AM PDT, ID: 21274769

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[+][-]04.03.2008 at 10:21AM PDT, ID: 21274780

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[+][-]04.04.2008 at 12:27AM PDT, ID: 21279584

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[+][-]04.04.2008 at 09:28AM PDT, ID: 21283325

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[+][-]04.04.2008 at 11:07AM PDT, ID: 21284243

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[+][-]04.07.2008 at 12:31AM PDT, ID: 21294860

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[+][-]04.07.2008 at 07:49AM PDT, ID: 21297443

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