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06.02.2008 at 08:34AM PDT, ID: 23450179
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8.5

SQL Like Statement not reporting correct information

Asked by ctstone14 in SQL Query Syntax, Databases Miscellaneous, MS SQL Server

Tags: , , ,

Here's my SQL statement:

SELECT *
FROM reportRec
WHERE ID LIKE'(SELECT reportNum FROM reportMPE WHERE MPEName IN  ("A-10 UPC v1.1"))%';

I do not get any syntax errors when executing it, but it is returning a blank query.  The embedded Select statement returns all the correct information in a seperate test query (which is a report number, such as 5555.555.555.5555).  So after that resolves, the SQL statement looks like this, which returns a blank query:

SELECT *
FROM reportRec
WHERE ID LIKE'(5555.555.555.5555)%';

The reason I am using the LIKE statement is because the ID field in the reportRec table contains appended report numbers (such as 5555.555.555.5555.01, .02, .03, etc.) and I would like for the query to return all of these appended reports, hence the % at the end.

Does my logic play out correctly, or should I be going at this in a different way?
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About this solution

Zones: SQL Query Syntax, Databases Miscellaneous, MS SQL Server
Tags: Microsoft, Access, 2003, SQL
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Solution Provided By: aaronakin
Participating Experts: 5
Solution Grade: A
 
 
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