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07.31.2008 at 04:25PM PDT, ID: 23612811
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8.6

Calculating exact age

Asked by IEHP1 in SQL Query Syntax

Hello Experts:  I have ran into a problem using SQL2000.  I'm attempting to calculate an age but I'm not getting the correct results.  I have a table with memberID and MemberDOB.  The member dob is being stored as varchar and looks like 19900801.  I need to get current age.  For example today this member would be 17.11 years. (dob: 19900801 and today is 20080731).  Everytime I run the code it gives me 18 yrs of age which is not correct.  Here's the code I'm using:

SELECT    MemberID, MemberDOB, convert(datetime,MemberDOB) as DOB,
                 convert(datetime,getdate(),101) as Today1,
                 datediff(year,convert(datetime,substring(MemberDOB,5,2) + '/' + right(MemberDOB,2) + '/' +    
                 left (MemberDOB,4)),convert(datetime,getdate(),101)) as age,
FROM        MemberTable

Thank you in advance for your help.
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Zone: SQL Query Syntax
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Solution Provided By: FrivolousSam
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