Advertisement

08.04.2008 at 10:03AM PDT, ID: 23619682
[x]
Attachment Details
[x]
The Solution Rating System

With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.

  • The Grade of the Solution
  • The Zone Rank of the Expert Providing the Solution
  • The Number of Author and Expert Comments
  • The Number of Experts Contributing
  • The Feedback of the Community

Your Input Matters
Because of the way the system is set up, the most important variable in this equation is you. As a member of Experts Exchange, you are able to cast your vote on the quality of the solutions in regard to how complete, accurate, helpful and easy to understand each solution is. When you provide your feedback, each rating is adjusted accordingly. So, if you see a solution that has a poor rating that you think is a good solution, let us know by rating it. As you do, the rating will be adjusted and will become more accurate for other members of our site.

If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support.

Thank you!
9.0

NESTED IF THEN STATEMENT IN SCALAR FUNCTION

Asked by AaronGreene1906 in SQL Query Syntax, SQL Server 2005

Tags: ,

I am attempting to write a series of functions that each have 3 parameters (year, month and business unit).  Each function will return the sum of a value for the entire year or a specific month for the entire division or a specific business unit.  I would like to be able to use the same function to return the value in each case.  The year will always be suppiled to the function, so there are 4 different options.

Start Free Trial 
1:
2:
3:
4:
5:
6:
7:
8:
9:
10:
11:
12:
13:
14:
15:
16:
17:
18:
19:
20:
21:
22:
23:
24:
25:
26:
27:
28:
29:
30:
31:
32:
33:
34:
35:
36:
37:
38:
39:
40:
41:
42:
43:
44:
45:
46:
47:
48:
49:
50:
51:
52:
53:

CREATE FUNCTION dbo.MR_METER_REPAIRS(@YEAR INT, @MONTH INT = 0, @BUNIT INT = 0)
RETURNS REAL 
AS 
BEGIN
DECLARE @RESULT REAL
IF @MONTH = 0 AND @BUNIT = 0 
BEGIN
SELECT @RESULT = ISNULL(SUM(X.TARGET),0)
FROM
(SELECT     DATEPART(Yy, txtWORKSTARTDATE) AS YEAR, DATEPART(Mm, txtWORKSTARTDATE) AS MONTH, cboBUNIT AS BIZUNIT, 
                      txtMETER_REPAIR AS TARGET
FROM         dbo.tblWorkOrder) X
WHERE X.YEAR = @YEAR
END
ELSE
BEGIN
IF @MONTH <> 0 AND @BUNIT = 0
BEGIN
SELECT @RESULT = ISNULL(SUM(X.TARGET),0)
FROM
(SELECT     DATEPART(Yy, txtWORKSTARTDATE) AS YEAR, DATEPART(Mm, txtWORKSTARTDATE) AS MONTH, cboBUNIT AS BIZUNIT, 
                      txtMETER_REPAIR AS TARGET
FROM         dbo.tblWorkOrder) X
WHERE X.YEAR = @YEAR
AND X.MONTH = @MONTH
END
ELSE
BEGIN
IF @MONTH = 0 AND @BUNIT <> 0
BEGIN
SELECT @RESULT = ISNULL(SUM(X.TARGET),0)
FROM
(SELECT     DATEPART(Yy, txtWORKSTARTDATE) AS YEAR, DATEPART(Mm, txtWORKSTARTDATE) AS MONTH, cboBUNIT AS BIZUNIT, 
                      txtMETER_REPAIR AS TARGET
FROM         dbo.tblWorkOrder) X
WHERE X.YEAR = @YEAR
AND X.BUNIT = X.BIZUNIT
END
ELSE
BEGIN
IF @MONTH <> 0 AND @BUNIT <> 0
BEGIN
SELECT @RESULT = ISNULL(SUM(X.TARGET),0)
FROM
(SELECT     DATEPART(Yy, txtWORKSTARTDATE) AS YEAR, DATEPART(Mm, txtWORKSTARTDATE) AS MONTH, cboBUNIT AS BIZUNIT, 
                      txtMETER_REPAIR AS TARGET
FROM         dbo.tblWorkOrder) X
WHERE X.YEAR = @YEAR
AND X.MONTH = @MONTH
AND X.BUNIT = X.BIZUNIT
END
RETURN @RESULT
END
[+][-]08.04.2008 at 11:56AM PDT, ID: 22154996

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]08.04.2008 at 12:01PM PDT, ID: 22155046

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]08.04.2008 at 08:04PM PDT, ID: 22157827

Often, when Experts are collaborating with members who have asked questions, they will request additional information about the problem. Askers respond with an author comment like this one.

Start your 7-day free trial to view this Author Comment or ask the Experts your question.

 
[+][-]08.04.2008 at 09:56PM PDT, ID: 22158239

View this solution now by starting your 7-day free trial. Setting up your free trial is quick, easy, and secure. We will return you to this solution, unlocked, when you're done.

 

About this solution

Zones: SQL Query Syntax, SQL Server 2005
Tags: SQL, SQL 2005
Sign Up Now!
Solution Provided By: angelIII
Participating Experts: 2
Solution Grade: A
 
 
 
Loading Advertisement...
20080716-EE-VQP-32 / EE_QW_2_20070628