Question

SQL Help Needed: date grouping, matching and counting

Asked by: dbnewbie

I need some SQL help. Here's my table:

ProfilePreviews:
- Id (PK)
- ProfileId(FK)
- ViewTypeId (FK)
- Date (DateTime)

The table records how many page views a particular profile has. There
are different types of page views (indicated by an ViewTypeId, say, 1
= Type1, 2 = Type2, 3 = Type3, etc.).

I need to generate a report that lists the counts for each view type
grouped by month for a particular ProfileId. An example output would
be:

Date          Type1          Type2          Type3
01-2008        5              10             12
02-2008        15             13             10
03-2008        25             15             14

                                  
1:
2:
3:
4:

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Asked On
2008-08-21 at 07:42:01ID23666938
Tags

SQL, MySQL

Topics

SQL Query Syntax

,

Databases Miscellaneous

,

MySQL Server

Participating Experts
1
Points
125
Comments
3

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Answers

 

by: KdoPosted on 2008-08-21 at 07:55:50ID: 22280179

Hi newbie,

There are several ways to do this.  Perhaps the easiest to understand is to produce a query that identifies the row with the appropriate type, and then just count them.


Good Luck,
Kent

//  This is the "core" query
SELECT Date,
  case when type = 1 then 1 else 0 end as type1,
  case when type = 2 then 1 else 0 end as type2,
  case when type = 3 then 1 else 0 end as type3
FROM {mytable}
WHERE ProfileID = {DesiredID};
//  Then just wrap it to get the answers
SELECT Date, sum(type1), sum(type2), sum(type3)
FROM
(
  SELECT Date,
    case when type = 1 then 1 else 0 end as type1,
    case when type = 2 then 1 else 0 end as type2,
    case when type = 3 then 1 else 0 end as type3
  FROM {mytable}
  WHERE ProfileID = {DesiredID};
) as t0
GROUP BY date;
                                              
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