Advertisement

10.13.2008 at 05:16AM PDT, ID: 23809232
[x]
Attachment Details
[x]
The Solution Rating System

With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.

  • The Grade of the Solution
  • The Zone Rank of the Expert Providing the Solution
  • The Number of Author and Expert Comments
  • The Number of Experts Contributing
  • The Feedback of the Community

Your Input Matters
Because of the way the system is set up, the most important variable in this equation is you. As a member of Experts Exchange, you are able to cast your vote on the quality of the solutions in regard to how complete, accurate, helpful and easy to understand each solution is. When you provide your feedback, each rating is adjusted accordingly. So, if you see a solution that has a poor rating that you think is a good solution, let us know by rating it. As you do, the rating will be adjusted and will become more accurate for other members of our site.

If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support.

Thank you!
9.1

select top 1 count(*) returning count of more than one record?

Asked by MMDeveloper in SQL Query Syntax, MS SQL Server, SQL Server 2005

Tags:

Ok I'm building a query to create a view in SQL server 2005 for work. One of the columns of the view is a simple 0/1 answer.

0 = the user in this record, has no records in TableB
1 = the user in this record has 1 or more records in TableB

So that column is simply a subquery (below)

The layout of TableB is as follows:
SHCDISTN
SHCRCD
SHCSTDT
SHCNBR
SCHCODE

there are no primary keys or relations to this table really. The SHCSTDT is a student number, so every medical 'code' has it's own record in the table with the corresponding student number. So student number "xyz" may have 3 records, no records, or 10000 record in TableB. Now given that, back to the subquery.

I figured I'd be tricky and simply do a count() for all records with that student number (xyz) but limit the result set to 1 (so the response is either 0 or 1 as desired).


The only issue is when the student number (xyz in this case) has 2 or more records in the table, instead of returning a "1", it returns the number of records they have, ignoring the "TOP 1" result set limit.

I come from a MySQL background so the MSSQL is still a little new to me. Am I missing a certain keyword or something? I've also tried to "group by SHCSTDT" but still get the same result. If needed I can clarify better.Start Free Trial 
1:
2:
3:
4:
5:
6:
7:
8:
9:

////////////sub query
      (
        SELECT TOP 1
            COUNT(SHCSTDT) AS total
        FROM
            dbo.SHC
        WHERE
            ( SHCSTDT = dbo.SBR.SBRSTDT )
      ) AS [Medical Problems]
 
Keywords: select top 1 count(*) returning cou…
Title
1 Access Query Record count
2 select query performace improvement …
3 PHP/MYSQL COUNT question
4 mysql subqueries
5 Query with subquery
6 MySQL, DELETE using subquery
 
Loading Advertisement...
 
[+][-]10.13.2008 at 05:22AM PDT, ID: 22701739

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]10.13.2008 at 05:25AM PDT, ID: 22701753

View this solution now by starting your 7-day free trial. Setting up your free trial is quick, easy, and secure. We will return you to this solution, unlocked, when you're done.

 

About this solution

Zones: SQL Query Syntax, MS SQL Server, SQL Server 2005
Tags: MSSQL
Sign Up Now!
Solution Provided By: Otana
Participating Experts: 2
Solution Grade: A
 
 
[+][-]10.13.2008 at 05:25AM PDT, ID: 22701759

Often, when Experts are collaborating with members who have asked questions, they will request additional information about the problem. Askers respond with an author comment like this one.

Start your 7-day free trial to view this Author Comment or ask the Experts your question.

 
[+][-]10.13.2008 at 05:34AM PDT, ID: 22701796

Often, when Experts are collaborating with members who have asked questions, they will request additional information about the problem. Askers respond with an author comment like this one.

Start your 7-day free trial to view this Author Comment or ask the Experts your question.

 
[+][-]10.13.2008 at 05:36AM PDT, ID: 22701812

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 7-day free trial to view this Expert Comment or ask the Experts your question.

 
 
Loading Advertisement...
20080716-EE-VQP-32 - Hierarchy / EE_QW_2_20070628