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8.0

SQl Query using Union

Asked by r_Shealy in SQL Query Syntax, MS SQL DTS, SQL Server 2005

Tags: SQL

I have this query which works fine except now I need to exclude the codes 220 and 221 from being in the result set.  Can someone help with this?
 I would guess I need to do something like what I did for the 400 code range but I am not sure how to go about it.
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SELECT DISTINCT LEFT(C.COMMENT_CODE,1) as C1, C.PTNO, 
MIN(C.COMMENT_CODE) AS COMMENT_CODE, P.HOSPITAL, C.RECORD_NUM 
FROM COMMENTS C
INNER JOIN PATIENT_TABLE P 
	ON C.PTNO = P.PTNO
LEFT JOIN COMMENTS TT
	ON TT.PTNO = C.PTNO 
		AND LEFT(C.COMMENT_CODE,1) = LEFT(TT.COMMENT_CODE,1) 
		AND TT.DATEENTERED < @DTBEGIN
WHERE LEFT(C.COMMENT_CODE,1) IN (1,2,3,5,8) AND C.COMMENT_CODE IS NOT NULL AND CAST(CONVERT(VARCHAR,C.DATEENTERED,101) AS DATETIME) BETWEEN @DTBEGIN AND @DTEND  
	AND P.HOSPITAL = @HOSPITALID
	AND TT.PTNO IS NULL
GROUP BY C.COMMENT_CODE, C.PTNO, P.HOSPITAL, C.RECORD_NUM
 
UNION
 
SELECT DISTINCT LEFT(C.COMMENT_CODE,1) as C1, C.PTNO, 
MIN(C.COMMENT_CODE) AS COMMENT_CODE, P.HOSPITAL, C.RECORD_NUM
FROM COMMENTS C
INNER JOIN PATIENT_TABLE P 
	ON C.PTNO = P.PTNO
LEFT JOIN COMMENTS TT
	ON TT.PTNO = C.PTNO 
		AND LEFT(C.COMMENT_CODE,3) = LEFT(TT.COMMENT_CODE,3) 
		AND TT.DATEENTERED < @DTBEGIN
WHERE LEFT(C.COMMENT_CODE,3) IN (400,401,402,403,404,405,406,407,408,409,410,411,412,413,414,415,416,417,418,419,420,421,422,427,428,429,430,431,432,435,436,437,438,439,440,446,447,448,449,450,451,452,455,456,466,467,468,471,472,473,474,475,476,477,478,480,481,484,486,487,488,489,490,491,492,493,494,495,496,497,498,499) AND C.COMMENT_CODE IS NOT NULL 
	AND CAST(CONVERT(VARCHAR,C.DATEENTERED,101) AS DATETIME) BETWEEN @DTBEGIN AND @DTEND
	AND P.HOSPITAL = @HOSPITALID
	AND TT.PTNO IS NULL
GROUP BY C.COMMENT_CODE, C.PTNO, P.HOSPITAL, C.RECORD_NUM
[+][-]12/04/08 08:29 AM, ID: 23096802Accepted Solution

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About this solution

Zones: SQL Query Syntax, MS SQL DTS, SQL Server 2005
Tags: SQL
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Solution Provided By: Focusyn
Participating Experts: 1
Solution Grade: A
 
[+][-]12/04/08 08:35 AM, ID: 23096867Author Comment

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