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9.3

SQL UNION and ORDER BY

Asked by andoneknight in SQL Query Syntax

Tags: SQL, Query, UNION, ORDER BY, Access, MS SQL

MyTable
ID   NAME         DAYSLEFT
1    "Tom"               4
2    "Dick"               1
3    "Harry"            -1
4    "Helga"            -3
5    "Brenda"           9

I wish to select all people from the above table, but I need it ordered as follows:

    If (DaysLeft > 0) ORDER BY DaysLeft ASC, Name ASC
    else ORDER BY Name ASC

Meaning:
    all people with a positive number of days left must be ordered least to most, then by name alphabetically if equal days left.
   and all other people (zero or less days left) are to be order by name alphabetically

The ordering by name is not so important in any case, but would be nice.

E.g.

Results
ID   NAME      DAYSLEFT
2    "Dick"            1
1    "Tom"            4
5    "Brenda"       9
3    "Harry"         -1
4    "Helga"         -3

The query I am trying to use at the moment, which doesn't give what I want is as follows:
SELECT * FROM (SELECT * FROM MyTable WHERE DaysLeft > 0 ORDER BY DaysLeft ASC, Name ASC) UNION ALL (SELECT * FROM MyTable WHERE DaysLeft <= 0 ORDER BY Name ASC)

And I have also tried the subtly different:
(SELECT * FROM MyTable WHERE DaysLeft > 0 ORDER BY DaysLeft ASC, Name ASC) UNION ALL (SELECT * FROM MyTable WHERE DaysLeft <= 0 ORDER BY Name ASC)
[+][-]08/20/09 04:06 AM, ID: 25140983Accepted Solution

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About this solution

Zone: SQL Query Syntax
Tags: SQL, Query, UNION, ORDER BY, Access, MS SQL
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Solution Provided By: angelIII
Participating Experts: 7
Solution Grade: A
 
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