[x]
Posted via EE Mobile

Search, ask, and monitor your questions on the go with EE Mobile. Visit Experts Exchange from your mobile device and never be out of touch again.

Question
[x]
Attachment Details
[x]
The Solution Rating System

With so many solutions, how can you tell which solutions are most likely to help you and which ones are not? To provide you with a tool to use, we rate our solutions based on various elements that most accurately determine if a solution is a quality solution. To explain what factors affect the solution rating, here are the elements we take into consideration when formulating our solution rating.

  • The Grade of the Solution
  • The Zone Rank of the Expert Providing the Solution
  • The Number of Author and Expert Comments
  • The Number of Experts Contributing
  • The Feedback of the Community

Your Input Matters
Because of the way the system is set up, the most important variable in this equation is you. As a member of Experts Exchange, you are able to cast your vote on the quality of the solutions in regard to how complete, accurate, helpful and easy to understand each solution is. When you provide your feedback, each rating is adjusted accordingly. So, if you see a solution that has a poor rating that you think is a good solution, let us know by rating it. As you do, the rating will be adjusted and will become more accurate for other members of our site.

If you have any suggestions that you would like to make for our rating system, please ask a question in the Suggestions Zone of Community Support.

Thank you!

9.1

sql - full record update w/o each field defined

Asked by dcass in SQL Query Syntax

Tags: sql

I have to update all records if duplicates in table, but don't have to type in 100 variables and worry about table design changes.  Is there any way to do this without specified each record in ASP (html/vbscript)?
1:
2:
3:
4:
5:
6:
7:
8:
9:
10:
11:
12:
13:
14:
if UpdateNotesFlag = "1" then 
 ' update other records for (multiple records) with new changes
        dupctr = 0
        SQL = "SELECT var1,id FROM OContacts WHERE var1 = '" + CustName + "'"
        SQL_Rs.open SQL,SQL_Cn,3
        if SQL_Rs.RecordCount > 1 then
            dupctr = cint(SQL_rs.recordcount)
        end if
        SQL_rs.close
        if dupctr > 1 then
              SQL = "update OContacts set var5='"+var5sv+"' where var1='" + CustName + "'"
              SQL_Rs.open SQL,SQL_Cn,3
        end if  
 end if
 
Loading Advertisement...
 
[+][-]10/20/09 08:02 PM, ID: 25620541Expert Comment

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 30-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]10/20/09 08:28 PM, ID: 25620629Expert Comment

At Experts Exchange, members can ask their questions to thousands of technology professionals, also known as Experts. Experts compete and collaborate to answer those questions by leaving comments like this one.

Start your 30-day free trial to view this Expert Comment or ask the Experts your question.

 
[+][-]10/21/09 09:03 AM, ID: 25625343Author Comment

Often, when Experts are collaborating with members who have asked questions, they will request additional information about the problem. Askers respond with an author comment like this one.

Start your 30-day free trial to view this Author Comment or ask the Experts your question.

 
[+][-]10/28/09 09:04 PM, ID: 25690572Author Comment

Often, when Experts are collaborating with members who have asked questions, they will request additional information about the problem. Askers respond with an author comment like this one.

Start your 30-day free trial to view this Author Comment or ask the Experts your question.

 
[+][-]10/29/09 04:06 AM, ID: 25692316Accepted Solution

View this solution now by starting your 30-day free trial. Setting up your free trial is quick, easy, and secure. We will return you to this solution, unlocked, when you're done.

About this solution

Zone: SQL Query Syntax
Tags: sql
Sign Up Now!
Solution Provided By: mark_wills
Participating Experts: 2
Solution Grade: A
 
 
Loading Advertisement...
20091111-EE-VQP-89 - Hierarchy / EE_QW_3_20080625