Question

Counting number of row, number of rows with a null in colx and the number of rows without a null in colx.

Asked by: RQuadling

Hi.

Am I missing anything by the snippet below.

Is summing the only way to count the values (not the distinct values)

SELECT
		@i_StartedWith = COUNT(*),
		@i_Dead = SUM(CASE WHEN CRR.DateRemoved IS NULL THEN 1 ELSE 0 END),
		@i_Live = SUM(CASE WHEN CRR.DateRemoved IS NULL THEN 0 ELSE 1 END)
	FROM
		dbo.CachedRemovalReasons CRR

                                  
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Asked On
2009-10-26 at 07:06:52ID24843580
Tags

SQL Syntax

,

Microsoft SQL Server 2005

,

count

Topics

SQL Query Syntax

,

SQL Server 2005

,

MS SQL Server

Participating Experts
3
Points
50
Comments
6

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Answers

 

by: tigin44Posted on 2009-10-26 at 07:15:50ID: 25662431

try this
SELECT
                @i_StartedWith = COUNT(*),
                @i_Dead = SUM(CASE WHEN CRR.DateRemoved IS NULL THEN 1 ELSE 0 END),
                @i_Live = SUM(CASE WHEN CRR.DateRemoved IS not NULL THEN 1 ELSE 0 END)
        FROM
                dbo.CachedRemovalReasons CRR

 

by: QlemoPosted on 2009-10-26 at 07:31:53ID: 25662586

tigin44,
That is exactly the same query as posted by the asker.

RQuadling,
There are other options, but I think the one used is the "best". You can count e.g. with

select i_dead+i_live, i_dead, i_live
from
(select count(*) i_dead from dbo.CachedRemovalReasons where DateRemoved is null) dead,
(select count(*) i_live    from dbo-CachedRemovalReasons where DateRemoved is not null) live
                                              
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2:
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by: shru_0409Posted on 2009-10-26 at 07:38:03ID: 25662642

SELECT COUNT(*) as i_StartedWith,
            count(CASE WHEN CRR.DateRemoved IS NULL THEN 1 ELSE 0 END) l_dead,
            count(CASE WHEN CRR.DateRemoved IS not NULL THEN 1 ELSE 1 END) i_Live
      FROM dbo.CachedRemovalReasons CRR

try his

 

by: RQuadlingPosted on 2009-10-26 at 07:50:26ID: 25662780

Thanks all, though I am shocked, dismayed and appalled that only tigin44 realized I was assigning the values to some variables and not outputting them in a select statement!

Gee - call yourselves experts!!!

 

by: QlemoPosted on 2009-10-26 at 08:12:59ID: 25663031

That does not make a big difference - it was the figure, to show alternatives. And I did realize you assign the values to vars - but it was totally unimportant. You already seemed to be able to do that yourself.

Did you realize that tigin44 did not answer your question at all? Your query is correct, and the slight variation he supplied does not change anything to that.

 

by: RQuadlingPosted on 2009-10-26 at 08:58:20ID: 25663620

You're right. Doh. I thought I saw something useful there. It was my own work - nearly ...

Brain dead. Busy. Cycled to work. Exhausted.

Need coffee.

Home time soon please ...

20120131-EE-VQP-002

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