Nathan Riley
asked on
Trapping for more variables on Splitting out name filed
Currently using the below code, but found some places it's not working. Examples that it returns nulls are:
John Smith and ASSC
John J. De La Smith
John Smith and ASSC
John J. De La Smith
Create Function FirstName
(
@name varchar(50)
)
RETURNS varchar(50)
AS
BEGIN
SET @name = REPLACE(REPLACE(REPLACE(@name, ' ', ' '), '.', '~'), ' ', '.')
SET @name = Case When parsename(@name, 1) in ('JR')
Then ISNULL(parsename(@name, 4) + ' ', '') + parsename(@name, 3)
Else ISNULL(parsename(@name, 4) + ' ', '') + ISNULL(parsename(@name, 3) + ' ', '') + parsename(@name, 2) End
RETURN REPLACE(@name, '~', '.')
END
GO
Create Function LastName
(
@name varchar(50)
)
RETURNS varchar(50)
AS
BEGIN
SET @name = REPLACE(REPLACE(REPLACE(@name, ' ', ' '),'.','~'), ' ', '.')
SET @name = Case When parsename(@name, 1) in ('JR')
Then parsename(@name, 2) + ' ' + parsename(@name, 1)
Else parsename(@name, 1) End
RETURN REPLACE(@name,'~','.')
END
GO
ASKER CERTIFIED SOLUTION
membership
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.