Question

Access JSON query

Asked by: yami_rider

How do I access the encoded JSON return?  Here is my formatted JSON result:

[{"id":"24695","name":"john"}]

Here is my calling code:
$.get("mail/findUser.php", {search:$('#email_to').val(), action:'Lookup'}, function(result) {  
alert("Queried ajaxemail" + result);
});    

Printing the alert message works, I get the JSON encoded return, but I need to access individual elements of the JSON encoded return such as the ID or name field.

$.get("mail/findUser.php", {search:$('#email_to').val(), action:'Lookup'}, function(result) {  
alert("Queried ajaxemail" + result);
});

                                  
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Asked On
2009-08-07 at 21:40:18ID24636572
Tags

JSON JQuery Javascript

Topics

JSON

,

Jquery

,

Asynchronous Javascript and XML (AJAX)

Participating Experts
2
Points
500
Comments
6

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Answers

 

by: hieloPosted on 2009-08-07 at 22:11:08ID: 25048412

try:

$.getJSON("mail/findUser.php", {search: encodeURIComponent($('#email_to').val()), action:'Lookup'}, function(json){
  alert("JSON Data: " + json[0].id + " " + json[0].name);
});

                                              
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by: hieloPosted on 2009-08-07 at 22:12:51ID: 25048415

if your array has multiple items:

$.getJSON("mail/findUser.php", {search: encodeURIComponent($('#email_to').val()), action:'Lookup'}, function(json){
  $.each(json,function(i){
  alert("JSON Data: " + json[i].id + " " + json[i].name);
  });
});

                                              
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by: yami_riderPosted on 2009-08-08 at 23:26:40ID: 25053060

Thanks Hielo, but for some reason I still cannot access the individual elements of the returned data. This is what is being returned:
[{"id":"24695","name":"john"}]

$.get("mail/findUser.php", {search: encodeURIComponent($('#email_to').val()), action:'Lookup'}, function(json) {        
$.each(json,function(i){
    alert(json); <-- This prints fine it prints the above JSON output [{"id":"24695","name":"john"}]
    alert("JSON Data: " + json[i].id + " " + json[i].name); <-- This is never printed
        });                       
              });
alert("Out of loop");         
});

Even removing the loop and trying to print alert("JSON Data: " + json[0].id + " " + json[0].name); does not print any results.

I believe the JSON is valid, can you think of anything else that may be causing the issue? Thank you

 

by: sebastianrsPosted on 2009-08-09 at 03:32:21ID: 25053638

It's NOT $.get("mail/findUser.php" but $.getJSON("mail/findUser.php" !!

 

by: hieloPosted on 2009-08-09 at 04:49:11ID: 25053837

Since you used $.get(...), the returned data is treated as a string.

I clearly posted $.getJSON(...).

If you do not want to use $.getJSON(...) you will need to use $.ajax() and use the dataValue:"json" option so that your returned data is treated as a json object in your callback function.

 

by: yami_riderPosted on 2009-08-09 at 14:12:27ID: 25056001

Hielo,

That was my mistake I overlooked that part and you are correct in making that change, the expected results come through.  

So that I am clear on the result. Using $.get will simply return a string value where as $.getJSON will return a JSON object.

In any case everything is working and I understand it now. Thank you again for your help.

20120131-EE-VQP-002

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