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2.6

jQuery plugin to organize 3 dropdown menus

Asked by ussher in Jquery, JavaScript, Asynchronous Javascript and XML (AJAX)

Tags: jquery, ajax, javascript

Im looking for a jQuery way to organize the contents of 3 dropdown menus.

each of the dropdown menus has a different list of characteristics.

MAKER             | MODEL            | TYPE
honda             xl            car
honda            at            car
honda            sx            bike
honda            tt            truck
mitsubishi      xl            truck
mistubishi      405            car
mitsubishi      at            bike


Once on item is selected from one list then the contents of the others are limited.  But selection can be made starting from any of the 3 lists.

So a user might start by selecting TYPE as 'car' then the contents of the other 2 lists would be limited to :

MAKER             | MODEL            | TYPE
honda             xl            car
honda            at            car
mistubishi      405            car

or they might start by selecting MAKER as 'honda' in which case the others would be limited to

MAKER             | MODEL            | TYPE
honda             xl            car
honda            at            car
honda            sx            bike
honda            tt            truck

or they might start by selecting MODEL as 'xl' in which case the others would be limited to

MAKER             | MODEL            | TYPE
honda             xl            cark
mitsubishi      xl            truck

Is there a plugin for jQuery that can handle this in this manner?

(The data is stored in a mysql database and the site is in php if this makes any difference.)

Thanks

---edit---
How I think it would work:
the values of the dropdown menu are populated by ajax that calls the database and requests all the values

MAKE
"SELECT make FROM `cars` WHERE 1 "

MODEL
"SELECT model FROM `cars` WHERE 1 "

TYPE
"SELECT type FROM `cars` WHERE 1 "

as each selection is selected the options for the remaining pages are re-requested.
MAKE
(honda selected)

MODEL
"SELECT model FROM `cars` WHERE make = 'honda' "

TYPE
"SELECT type FROM `cars` WHERE make = 'honda' "

Then on the next level
MAKE
(honda selected)

MODEL
(xl)

TYPE
"SELECT type FROM `cars` WHERE make = 'honda' AND MODEL = 'xl'

[+][-]07/24/09 12:51 AM, ID: 24932860Accepted Solution

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About this solution

Zones: Jquery, JavaScript, Asynchronous Javascript and XML (AJAX)
Tags: jquery, ajax, javascript
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Solution Provided By: x_com
Participating Experts: 2
Solution Grade: C
 
[+][-]07/24/09 03:42 AM, ID: 24933587Author Comment

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[+][-]07/30/09 01:17 PM, ID: 24984001Expert Comment

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[+][-]07/30/09 07:20 PM, ID: 24986169Author Comment

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