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01.05.2008 at 04:36PM PST, ID: 23061382
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9.2

Malfunctioning Ajax Script

Asked by GarrettChristopherson in JavaScript

Tags: ,

With no success, I have tried using the following Javascript and PHP code:  Could someone help show what the problem is with this code or find an explanation why the code does not appear to work on my web page?Start Free Trial
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<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<title>AjaxTest</title>
<script language="javascript">
var menu;
function getmenu(menuNumber)
{
	var XMLHttpRequestObject = false;
	if(window.XMLHttpRequest) {
		XMLHttpRequestObject = new XMLHttpRequest();
		XMLHttpRequestObject.overrideMimeType("text/xml");
	}  else if (window.ActiveXObject){
		XMLHttpRequestObject = new ActiveXObject("Microsoft.XMLHTTP");
		}
	if( XMLHttpRequestObject){
		XMLHttpRequestObject.open("GET", "menus.php?menu="+menuNumber);
		XMLHttpRequestObject.onreadystatechange = function(){
			if(XMLHttpRequestObject.readyState == 4 && XMLHttpRequestObject.status == 200){
				var xmlDocument = XMLHttpRequestObject.responseXML;
				menu = xmlDocument.getElementsByTagName("menuitem");
				listMenu();
			}
		}
		XMLHttpRequestObject.send(null);
	}
}
function listMenu ()
{
	var loopIndex;
	var selectControl = document.getElementById('menuList');
	for(loopIndex = 0; loopIndex < menu.length; loopIndex++)
	{
		selectConrol.options[loopIndex] = new Option(menu[loopIndex].firstChild.data);
	}
}
 
function setmenu()
{
	document.getElementById('targetDiv').innerHTML = "You Selected " + menu[document.getElementById('menuList').selectedIndex].firstChild.data;
}
</script>
</head>
 
<body>
<h1> Using multiple XMLHttpRequest object</h1>
	<form>
		<select size="1" id="menuList" onChange="setmenu()">
			<option> Select a menu item</option></select>
			<br>
			<br>
			<input type="button" value = "Select Menu 1" onClick="getmenu('1')">
			<input type="button" value="Select Menu 2" onClick="getmenu('2')">
			</form>
			<div id = "targetDiv" width = 100 height = 100> Your lunch selection will appear here.</div>
</body>
</html>
 
<?
header ("Content-type: text/xml");
if($_GET["menu"] == "1")
$menuitems = array('Ham', 'Turkey', 'Beef');
if($_GET["menu"] =="2")
$menuitems = array('Tomato', 'Cucumber', 'Rice');
echo '<?xml version = " 1.0" ?>';
echo'<menu>';
foreach($menuitems as $value)
{
	echo'<menuitems>';
	echo $value;
	echo'</menuitem>';
}
echo '</menu>';
?>
[+][-]01.05.2008 at 04:49PM PST, ID: 20591962

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[+][-]01.05.2008 at 05:17PM PST, ID: 20592064

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[+][-]01.05.2008 at 05:36PM PST, ID: 20592112

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[+][-]01.05.2008 at 05:42PM PST, ID: 20592126

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[+][-]01.05.2008 at 06:02PM PST, ID: 20592193

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[+][-]01.05.2008 at 07:32PM PST, ID: 20592384

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[+][-]01.06.2008 at 04:07AM PST, ID: 20593621

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[+][-]01.06.2008 at 04:09AM PST, ID: 20593626

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[+][-]01.06.2008 at 07:22PM PST, ID: 20596936

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About this solution

Zone: JavaScript
Tags: Javascript, Opera 9.25
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Solution Provided By: hielo
Participating Experts: 3
Solution Grade: A
 
 
 
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