Question

Javascript decimal verfication

Asked by: GSRacer

I'm trying to write a script to validate a numeric value. My code currently remove leading zeros and validates that the value is numeric.

What I need to add is to verify if a decimal is present, it does not occur more than 2 places.

Valid - 085.33
Invalid - 085.333

The code is embedded into EDIFECS Specbuilder software and contains objects specific to it.

Thanks!

if (ec_DataLink.m_bDataPresent)
{
	vMonAmt = ec_DataLink.m_sData;
	while (vMonAmt.length > 0) 
	{
    	if (vMonAmt.substring(0, 1) != "0" || vMonAmt.substring(0, 1) != " " )
      	break;
    	vMonAmt = vMonAmt.substring(1, vMonAmt.length);
	}
 
	if (vMonAmt != parseFloat(vMonAmt))
	{
		ec_ErrorContainer.AddError("Monetary Amount data element is non-numeric.   " + ec_strErrorElemMsg);
	}
}

                                  
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Asked On
2008-12-30 at 08:38:39ID24015908
Tags

javascript pattern matching numeric decimal verification

Topic

JavaScript

Participating Experts
1
Points
500
Comments
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Answers

 

by: SnowFlakePosted on 2008-12-30 at 10:27:36ID: 23264634

you can check if (''+vMonAmt+'.').split('.')[1].length<=2

SnowFlake

 

by: SnowFlakePosted on 2008-12-30 at 10:32:38ID: 23264676

whatever way you choose
test it on
012.3123
012.31
.3123
.31
and
31

SnowFlake

 

by: GSRacerPosted on 2008-12-30 at 11:12:49ID: 31529733

Perfect! I implemented your code as is with the exception of the operator. I used > instead of <= as I want to throw an error if there are more than 2 decimal places.

Thanks again.

 

by: SnowFlakePosted on 2008-12-30 at 13:09:34ID: 23266089

your welcome.

20120131-EE-VQP-002

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